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This question already has an answer here:

This is a plot of my data

enter image description here

These are the values:

   xvalues  yvalues
1   1.091186
2   2.653722
3   3.309146
4   5.206479
5   5.115582
6   8.537005
7   10.013147
8   9.802291
9   10.667769
10  5.809750
11  9.624475
12  11.806013
13  13.587066
14  14.146781
15  13.707472
16  12.891355
17  19.435301
18  16.122108
19  17.768536
20  23.813027
21  21.819081
22  23.556074
23  21.170983
24  27.621148
25  22.932580
26  20.704689
27  25.530339
28  26.227371
29  26.051016
30  31.047145

I now do a PCA and a biplot of it:

enter image description here

According to Jeromy Anglim in: Interpretation of biplots in principal components analysis in R

The left and bottom axes are showing the loadings; the top and right axes are showing principal component scores.

The left and bottom axes are showing [normalized] principal component scores; the top and right axes are showing the loadings.

I want to be sure I really get this.

Let's start with the loadings: these can be visualized in R by writing:

results <- prcomp(your_data)
results$rotation 

          PC1        PC2
xvalues   0.7235616  -0.6902599
yvalues   0.6902599   0.7235616

summary(results)

Importance of components:
                       PC1     PC2
Standard deviation     12.0747 1.56606
Proportion of Variance  0.9835 0.01654
Cumulative Proportion   0.9835 1.00000

Now lets look at the red arrow of xvalues. Its tip is around 0.25 in the x-axis of the loadings. But according to the loadings I have just writen, it should be around 0.72. What am I missing?

Finally, lets look at the point 1. According to the axes, that is telling me the principal component score. Is it that the coordinate in the new frame of reference? It doesn't make sense to me because I think that the new origin of the axes is around the point (15,15) in the Plot 3. If I look at that (and I guess that I am completely wrong here), the point one should have a coordinate around -20 or so, and not 40. Where is my mistake?

Update

I tried plotting this:

plot(pca_results$x)

enter image description here

Here it can be seen that the first point has the coordinate that I thought it had to have. But, still, what are the units in the biplot then??

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marked as duplicate by amoeba says Reinstate Monica, Nick Cox, kjetil b halvorsen, Andy, Xi'an Jan 14 '15 at 20:00

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

  • $\begingroup$ Your last paragraph is a bit mystical because it seems to not correspond to your pictures. PCA biplot is can be interpreted as the overlay scatterplot, a superposition of two scatterplots in the same axes (the PCs): plot of the data scores and plot of the variable loadings. You might also want to glance here. $\endgroup$ – ttnphns Dec 25 '13 at 20:11
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    $\begingroup$ On your first biplot, the data cloud is round dispite that according to you data PC1 must be much stronger than PC2. This makes me to think that the PC scores on the biplot are standardized (to st. dev. 1). Check if this is true. The loading points (red arrows) are likely to be loadings, as they should. The results$rotation figures you present are clearly the eigenvector values, not the loadings. Please be aware that the R PCA package you use misuses the word "loadings", incorrectly calling eigenvectors "loadings". $\endgroup$ – ttnphns Dec 26 '13 at 12:22
  • $\begingroup$ How do I check the loadings then? $\endgroup$ – Adrián A.D. Dec 26 '13 at 12:32
  • $\begingroup$ By definition, "matrix of loadings" (prior rotation or after orthogonal rotation") must have column sum of squares equal to the variances of corresponding factors/components. Thus, in PCA, loadings after extraction and prior rotation are the eigenvectors multiplied by the sq. root of their corresponding eigenvalues (because eigenvalue is the component's variance, prior rotation). $\endgroup$ – ttnphns Dec 26 '13 at 12:44
  • $\begingroup$ I don't know what your results$rotation matrix actually is. It could be eigenvectors (prior rotation) or it could the orthogonal rotation matrix. Because you didn't show the original data (the values) and full output of your PCA, I can't say. $\endgroup$ – ttnphns Dec 26 '13 at 12:50
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I redid your PCA in SPSS (I'm not R user). It was PCA based on covariances. I confirm your analysis.

Eigenvalues (component variances) and the proportion of overall variance explained
I    145.7983424      .9834567
II     2.4525573      .0165433

Eigenvectors (cosines of rotation of variables into components)
         I             II
X   .7235615578  -.6902598583
Y   .6902598583   .7235615578

Loadings (eigenvectors normalized to respective eigenvalues; loadings are the covariances between variables and components)
         I             II
X   8.736787614  -1.080991303
Y   8.334679634   1.133143904

Raw componenet scores (Centered XY data multiplied by eigenvectors)
         I             II
  -20.36311916    -.33895962
  -18.56100172     .10137150
  -17.38502729    -.11464875
  -15.35181292     .56792862
  -14.69099392    -.18810082
  -11.60576140    1.59724948
   -9.86327828    1.97506923
   -9.28526215    1.13224207
   -7.96429587    1.06820882
  -10.59402982   -3.13712683
   -7.23731673   -1.06719832
   -5.00792706    -.17898115
   -3.05497611     .41946048
   -1.94506575     .13418887
   -1.52474156    -.87393809
   -1.36451281   -2.15470883
    3.87607199    1.88997907
    2.31266941   -1.19757988
    4.17269413    -.69654773
    9.06852519    2.98675374
    8.41574586     .85375121
   10.33828396    1.42031271
    9.41551294    -.99570731
   14.59136448    2.98112427
   12.07859576   -1.10160316
   11.26433359   -3.40387930
   15.31884763    -.60248432
   16.52354240    -.78839862
   17.12537318   -1.60626218
   21.29756203    1.31848485

The component scores that you plotted as plot(pca_results$x) are these raw component scores printed above.

The component scores on your biplot are these scores scaled to sum-of-squares=1 (sum of squares in each of the 2 columns was brought to 1).

As for the loadings shown as red arrows on the biplot, they are, without doubt, rescaled loadings that I printed above. However - since I'm not R user - I can't tell you how exactly they were rescaled. But I suppose they linearly are related to the true loadings I printed. Biplots can be drawn in multiple ways, with various normalizations. I can't know how your R function exactly does it, and probably it is not too important to know it.

Another my example, even more full, is here. It is the outputs of PCA and LDA (linear discriminant) analyses of iris data.

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  • 1
    $\begingroup$ According to What are the four axes on PCA biplot?, in the default biplot in R the eigenvectors are scaled by the respective standard deviation (square root of the respective eigenvalue) -- this results in loadings -- and then additionally scaled by the square root of the number of observations. $\endgroup$ – amoeba says Reinstate Monica Jan 14 '15 at 18:13

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