4
$\begingroup$

I've been trying to create a multivariate regression model to fit my training data into the prediction of a value. I've put my data into a matrix X with m x n where m is the number of instances and n the number of features/predictors. My label vector is then m x 1. This is my code to predict the theta values, or parameters.

theta_matrix =  pinv(X'*X)*X'*y_label;

Now I want to slip the data into train and test, and by researching I've found that cross-validation in 10-fold can be a good option. If I do so, wouldn't it get me 10 sets of parameters theta? So what to choose from then?

And about feature selection, I've found that stepwise can be a good choice, but I think it does not take into account that features can be correlated. Any alternative?

$\endgroup$
  • 1
    $\begingroup$ There's often confusion about the (primary) use of cross-validation to validate a model-selection procedure for a particular data-set, & its (secondary) use as part of a model-selection procedure. In this case you're cross-validating the procedure that gave you one set of parameter estimates, not picking the best of the ten sets - they're disposable. If you were to do the latter, that procedure would itself need to be validated. Dikran's explanation here is good & clear. $\endgroup$ – Scortchi - Reinstate Monica Feb 25 '14 at 11:53
4
+50
$\begingroup$

You can use cross-validation to understand how your model would behave on completely new or 'unseen' data.

You should also use cross-validation to select which features to use - try sequential feature selection (sequentialfs in Matlab) or Lasso (lasso in Matlab). cvpartition command in Matlab will allow you to setup your test/train partitions for cross-validation, sequentialfs will take a partition object as an input.

Once you have an idea of how your model will behave on unseen data. You can decide what features to use and generate your 'final' model by running the same routine on all available data, which will give a single set of coefficients.

An excellent answer on a similar topic is here

$\endgroup$
  • $\begingroup$ I understand how to use sequenctialfs in a classification problem, not in a regression problem. $\endgroup$ – SamuelNLP Feb 24 '14 at 14:54
  • 1
    $\begingroup$ Matlab provide an example here: mathworks.co.uk/help/stats/feature-selection.html#brluyid-1 $\endgroup$ – BGreene Feb 24 '14 at 14:57
  • $\begingroup$ So I have to give the error to the function sequentialfs, would it be the estimated error from the y_label - y_new_label? $\endgroup$ – SamuelNLP Feb 24 '14 at 15:05
  • $\begingroup$ so depending on the partition, the feature selection will differ. $\endgroup$ – SamuelNLP Feb 24 '14 at 15:06
  • 1
    $\begingroup$ You run the same feature selection routine on all data - this produces your 'final' feature set. See answer here: stats.stackexchange.com/questions/2306/… $\endgroup$ – BGreene Feb 24 '14 at 15:39
1
$\begingroup$

"And about feature selection, I've found that stepwise can be a good choice, but I think it does not that into account that features can be correlated. Any alternative?"

Stepwise regression is a great way to do feature selection. Make sure you are using a metric that penalizes for incorporating more features though. For example stepwise regression on just $R^2$ may not be useful, but stepwise regression on AIC may be useful.

In general I remove correlated features before doing stepwise regression (although in theory stepwise regression using AIC shouldn't pull in two correlated features). I do this by looking at pairwise correlation but also by looking at multicollinearity, in particular VIF.

Finally, instead of doing any feature selection, you can do principal components analysis or another dimension-reduction technique to reduce your number of inputs. When I've done in practice, I then use cross-validation to pick how many of the reduced dimensions to use. For example I make $X$ different models that are trained on $1,2,3,4,...X$ lower dimensions and then see which model performs the best in terms of cross-validation.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.