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In my elementary statistics course, I learnt how to construct 95% confidence interval such as population mean, $\mu$, based on asymptotic normality for "large" sample sizes. Apart from resampling methods (such as bootstrap), there is another approach based on "profile likelihood". Could someone elucidate this approach?

Under what situations, the constructed 95% CI based on asymptotic normality and profile likelihood are comparable? I could not find any references on this topic, any suggested references, please? Why isn't it more widely used?

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In general, the confidence interval based on the standard error strongly depends on the assumption of normality for the estimator. The "profile likelihood confidence interval" provides an alternative.

I am pretty sure you can find documentation for this. For instance, here and references therein.

Here is a brief overview.

Let us say the data depend upon two (vectors of) parameters, $\theta$ and $\delta$, where $\theta$ is of interest and $\delta$ is a nuisance parameter.

The profile likelihood of $\theta$ is defined by

$L_p(\theta) = \max_{\delta} L(\theta, \delta)$

where $L(\theta, \delta)$ is the 'complete likelihood'. $L_p(\theta)$ does no longer depend on $\delta$ since it has been profiled out.

Let a null hypothesis be $H_0 : \theta = \theta_0$ and the likelihood ratio statistic be

$LR = 2 (\log L_p(\hat{\theta}) - \log L_p(\theta_0))$

where $\hat{\theta}$ is the value of $\theta$ that maximises the profile likelihood $L_p(\theta)$.

A "profile likelihood confidence interval" for $\theta$ consists of those values $\theta_0$ for which the test is not significant.

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    $\begingroup$ @ocram- Thanks for the clarification. It seems the method requires some intensive computations, maximizing the profile likelihood. Just wondering why not simply resort to the bootstrap method if the estimator is not normally distributed. $\endgroup$
    – user2264
    Apr 21, 2011 at 17:46
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    $\begingroup$ Bootstrap is also an asymptotic methods, and compute intensive in itself, so not the natural answer if you want to avoid intensive computation ... $\endgroup$ Feb 28, 2015 at 11:03
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    $\begingroup$ Could you please tell me does coverage probability of profile confidence interval greater than coverage probability based on asymptotic standard normal ? $\endgroup$
    – time
    Jul 30, 2015 at 13:47
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    $\begingroup$ @time: I don't know... I guess it depends on whether the asymptotic standard normal distribution is valid. A small simulation study should be quite easy to put into place to get some insight. $\endgroup$
    – ocram
    Jul 30, 2015 at 14:12

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