Linked Questions

1 vote
1 answer
12k views

Calculate moment generating function of normal distribution [duplicate]

The moment generating function of a normal distribution is defined as $M(t) = \int_{-\infty}^\infty e^{tx}\frac{1}{\sqrt{2\pi\sigma^2}} e^{-\frac{1}{2}(\frac{x-\mu}{\sigma})^2} dx$ In a book I’m ...
Arturo Sbr's user avatar
0 votes
1 answer
558 views

Standard normal moments [duplicate]

My textbook says, without proof, that $E(X^4)=3$, where $X\sim N(0,1)$. Is it so simple to obtain?
Zirui Wang's user avatar
2 votes
0 answers
169 views

The $k$th moments of normal distribution [duplicate]

How to proof that the $k$th moments of random variable $X\backsim N(0, \sigma^2)$ which is: $$ E(X^k) = \begin{cases} \sigma^k(k!!) & \text{for k even;}\\ \ 0 & \text{for k odd} \end{cases} $...
Vita's user avatar
  • 21
1 vote
0 answers
35 views

Problem with the expectation of transformed random variable [duplicate]

I read a paper where the random variable $z$ is assumed to follow a log-normal distribution. \begin{equation} \mathbb{E}\left(z^{1-\chi}\right)=\int_{0}^{\infty}z^{1-\chi}\frac{1}{z\sqrt{2\pi s^{2}}}e^...
optimal control's user avatar
0 votes
0 answers
27 views

Second order moment of the Gaussian Distribution [duplicate]

In Bishops book, "Statistical Pattern Recognition", there is one exercise, which states to derive the second order moment of the Gaussian Distribution: $E[x^2] = \int_{-\infty}^{\infty} N(x|...
kklaw's user avatar
  • 535
2 votes
2 answers
9k views

Rationale for $E[Z^4]=3$

Given $Z$ is a standard normal random variable with mean 0 and variance 1 ($Z \sim N(0,1)$), could anyone provide an explanation for why $E\left[ Z^4 \right] = 3$? I know that: $$ \begin{aligned} E \...
Chris C's user avatar
  • 2,630
4 votes
1 answer
2k views

Expected value of functions of Gaussian random variable

I am trying to compute the following expectations: (i) $E\left[\frac{1}{a^X}\right]$, (ii) $E\left[\frac{X^2}{a^X}\right]$, (iii) $E\left[\frac{X}{a^X}\right]$. In above, $a$ is a constant and $X$ ...
John Majimboni's user avatar
5 votes
1 answer
795 views

Possible to use moment generating function of standard normal to find variance of noncentral $\chi^{2}$?

In a homework problem, I have been asked to find the variance of the noncentral $\chi_{n,\delta}^{2}$ distribution with degrees of freedom $n$ and noncentral parameter $\delta >0$ by using the ...
NotThatGrumpyAnymore's user avatar
3 votes
1 answer
837 views

How to compute this moment of a bivariate normal distribution?

Consider that $X \sim N(\mu_X, \sigma_X^2)$ and $Y \sim N(\mu_Y, \sigma^2_Y)$ and $\text{Cov}[X, Y] = \sigma_{XY}$ where $\sigma_{XY} \ne 0$. How can an expression for $\text{E}[Y(X-\mu_X)^p]$ in ...
SeanBrooks's user avatar
0 votes
0 answers
3k views

expected value of Brownian Motion

Suppose I have a brownian motion $B(t)$, how to calculate the Expected value of $B(t)$ to the power of any integer value $n$? Intuition told me should be all 0. But how to make this calculation?
rifle123's user avatar
  • 335
2 votes
1 answer
2k views

Moment generating function of a (normally distributed) random variable

I am given 3 things: $Z$ follows a normal distribution $N(0,1)$ $Y=e^{X}$ $X=3-2Z$ What is the moment generation function of $X$ and the $r^{th}$ moment of $Y$ ($E[Y^{r}]$)? My attempt: I know ...
ozarka's user avatar
  • 189
4 votes
1 answer
292 views

Help getting the variance of $Y$

We have $Z \sim N(0,1)$ and $Y=a+bZ+cZ^2$. What is the variance of $Y$? This is what I did: $$\mbox{Var} (Y)=0+b^2 \, \mbox{Var} (Z)+c^2 \, \mbox{Var} (Z^2) = b^2 + c^2 \, \mbox{Var} (Z^2)$$ To get ...
neto333's user avatar
  • 49
2 votes
0 answers
1k views

Fourth moment of complex Gaussian r.v

Let $x \sim \mathcal{CN}(0,a)$ (a complex Gaussian random variable) and I know that the p.d.f. of $z$ is defined by: $$p(z) = \frac{1}{\sqrt{2\pi a}} e^{-\frac{|z|^2}{2a}}$$. Given that, how can I ...
Felipe Augusto de Figueiredo's user avatar
1 vote
0 answers
803 views

MVUE and Cramer-Rao Lower Bound [duplicate]

Let $(X_1,...,X_n)$ be a random sample from a normal distribution $N(\mu,1)$. $T=\frac{1}{n}\sum_{i=1}^{n}X_{i}^2-1$ is an unbiased estimator for $\mu^2$ since : $$ E(T)=E(\frac{1}{n}\sum_{i=1}^{n}X_{...
Bahgat Nassour's user avatar
1 vote
0 answers
597 views

How to calculate E(1/Y) when Y is Inverse Gaussian distributed?

The Inverse Gaussian Distribution density is : $$\frac{\phi^{\frac{1}{2}}}{\sqrt{2\pi y^3}} exp[\frac{-\phi(y - \mu)^2}{2\mu^2y}]$$ Got to this integral: $$\int_0^\infty \frac{1}{y} \frac{\phi^{\frac{...
VFreguglia's user avatar

15 30 50 per page