Skip to main content

All Questions

Filter by
Sorted by
Tagged with
9 votes
4 answers
5k views

Why highly correlated means higher variance?

I am reading the book Introduction to Statistical Learning and on page 183, the book states that Since the mean of many highly correlated quantities has higher variance than does the mean of many ...
Dat Nguyen's user avatar
4 votes
2 answers
985 views

Intuitive understanding of variance of sum vs variance of difference

$\newcommand{\Var}{\operatorname{Var}}\newcommand{Cov}{\operatorname{Cov}}$Mathematically, $\Var(X + Y) = \Var(X) + \Var(Y) + 2\Cov(X,Y)$ and $\Var(X - Y) = \Var(X) + \Var(Y) - 2\Cov(X,Y)$ This ...
Hank Lin's user avatar
  • 529
12 votes
1 answer
3k views

Understanding $\operatorname{Cov}(X,X) = \operatorname{Var}(X)$ intuitively

I just saw this question and the wonderful accepted answer in this forum. I was then triggered to try understanding intuitively why division of $S_xS_y$ is normalizing the covariance: $$\frac{\...
d_e's user avatar
  • 223