I'm supposed to perform a hypothesis test with:

sample size = $27$

sample mean = $10.7$

sample standard deviation = $3.6$

Hypothesized mean, $\mu_0=11$

Because the sample size is small and population standard deviation is unknown, I perform a t-test to see if I can reject my null hypothesis.

I find that the t-score is $-0.43$ and:

$\text{p-value} =2p(t_{26} > 0.43)$

This is the t-table I will be provided in tests/exams at my school: https://drive.google.com/file/d/0BxUaD_pbAL2hQzE0dzZtVHhsSlU/view

There is no value close to $0.43$ in the row of $\text{df} = 26$ on the t-table, so what do I do? 

Am I supposed to use the z-table instead? Or is using R or some other computational program the only possible way to find the p-value?

Also, regarding the t-table I linked, is this table only for one-tailed t-tests? If so, what do I do if I need to do a two-tailed test (like in this example)?