Here is a exercise from *Mathematical Statistics. Jun Shao. Second edition. EX2.20

Let $X_1,..., X_n$ be $i.i.d.$ random variables having the exponential distribution $E(a,\theta)$, $a\in R$, and $\theta > 0$. 

$$
      f(x,a,\theta)=\frac{1}{\theta}e^{-(x-a)/\theta}I(x>a)
$$

$$
      F(x)=1-e^{-(x-a)/\theta}
$$

Show that the smallest order statistic, $X_{(1)}$, has the exponential distribution $E(a,\theta/n)$ and that $2\sum\limits_{i=1}^{n}(X_{i}-X_{(1)})/\theta$ has the chi-square distribution $\chi^2_{2n-2}$.

What I know is:

The p.d.f. of $X_{(1)}$ is:
$$
     f(x)=\frac{n!}{(n-1)!}\left[\frac{1}{\theta}e^{-(x-a)/\theta}\right]\left[e^{-(x-a)/\theta}\right]^{n-1}=\frac{1}{\theta/n}\exp\left\{-\frac{x-a}{\theta/n}\right\}\sim E(a,\theta/n)
$$

I don't know how to caculate the p.d.f. of $2\sum\limits_{i=1}^{n}(X_{i}-X_{(1)})/\theta$ ; 

But I know how to caculate the p.d.f. of $2\sum\limits_{i=1}^{n}(X_{(i)}-X_{(1)})/\theta$ . 

My question is that can we assume $\sum\limits_{i=1}^{n}X_{i}$ and $\sum\limits_{i=1}^{n}X_{(i)}$ are the same?

If we can not, can you give one example to explain? and how to solve the question above.