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2
votes
1
answer
421
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Posterior predictive distribution and posterior predictive checks
To obtain a random draw from the posterior predictive distribution I would concatenate the $(y_{rep}^{(1)}, \ldots, y_{rep}^{(B)})$ vectors, marginalising out the posterior distribution (see for example … At that point, I would overlay the KDE of the observed outcome with the KDE of (what I believe is) the posterior predictive distribution. …
4
votes
1
answer
6k
views
JAGS: posterior predictive distribution
predictive distribution
for (j in 1:length(pvr)){
pmu[j] <- alpha + b.vr*pvr[j] + b.ir*pir[j]
pri[j] ~ dnorm(pmu[j],tau)
}
#priors for regression
alpha ~ dnorm(0,0.01 … )
b.vr ~ dunif(-10,0)
b.ir ~ dunif(0,10)
#prior for precision
tau ~ dgamma(0.001,0.001)
sigma <- 1/sqrt(tau)
}
I am trying to calculate the posterior predictive distribution with …
5
votes
1
answer
412
views
Sum over Posterior Predictive Distribution
I am confused about the posterior predictive distribution.
This is from Murphy's Machine Learning: A Probabilistic Perspective. … Should the posterior predictive distribution sum to 1? …
2
votes
1
answer
535
views
Generate data from posterior predictive distribution [closed]
I want to draw data from the posterior predictive distribution p(y|D). … my model has a complicated posterior predictive distribution p(y|D), so I cannot derive CDF. if I can use monte Carlo, can I draw data with pdf? …
1
vote
0
answers
129
views
Ranking or posterior predictive distribution
However, instead of deriving a posterior predictive distribution, the authors resort to ranking (Eq. 1). … Can you please clearly explain the differences between ranking and predictive posterior distribution for prediction? …
2
votes
1
answer
643
views
Posterior predictive distribution(Bayes regression)
=\theta^{T}x^{(i)}+e^{(i)}$$
where:
$$P(y^{(i)}|x^{(i)},\theta)=\frac{1}{\sqrt{2\pi}\sigma}exp(-\frac{(y^{(i)}-\theta^{T}x^{(i)})^{2}}{2\sigma^{2}})$$
Then using Bayes Rule we obtain some parameter distribution … My problem is with derivation of posterior predictive distribution which is given in notes as follows:
Given new test point $x_{*}$ probability distribution over possible outputs(posterior predictive …
4
votes
1
answer
665
views
Formulating posterior predictive distribution from hierarchical model
I think the struggle is in relation to the posterior predictive distribution. … Could anyone walk me through the probability/integration steps necessary to come up with this specific posterior predictive distribution?
1. Schofield et al. 2016↩
2. …
5
votes
1
answer
1k
views
Posterior predictive distributions and predictive intervals
As I understand it, in Bayesian inference, the posterior predictive distribution is the probability distribution of a new data point, as opposed to the posterior distribution which is a distribution of … However, to obtain the posterior predictive distribution, you marginalise over the parameter by integrating over it. …
1
vote
1
answer
525
views
Posterior Predictive Distribution of a Parameter
of a new data sample $y_{n+1}$
$$
p(y_{n+1} | y_1, \ldots, y_n; \mu_0, \sigma^2) \sim \mathcal{N}\left(\alpha_n, \sigma^2 +\tau_n^2\right)
$$
I am interested in computing the posterior predictive distribution … I can draw samples $\tilde{y}^i_{n+1}$ from the posterior predictive distribution of the data and construct an approximate average $\frac{1}{S} \sum_{i=1}^S p(\mu_{n+1} | y_1, \ldots, y_n, y^i_{n+1}; \ …
4
votes
1
answer
1k
views
Truncating a posterior predictive distribution in JAGS
In my minimum reproducible example, I have data for 9 observations and would like to find a posterior predictive distribution for the 10th observation. … To do this, I include the 10th observation as an NA and estimate its posterior predictive distribution as the variable pi10. …
1
vote
0
answers
29
views
How to derive conditional posterior predictive distribution from definition of posterior pre...
In my situation, I have a set of data points:
$$ z_{0:n} = \\{ (x_0, y_0),\dots ,(x_{n-1}, y_{n-1}) \\} $$
I am trying to figure out how to derive the fully expanded form for the conditional posterior … predictive distribution:
$$p(y|x, \mathcal{z}_{0:n})$$
from the definition of the posterior predictive distribution $(z=(x,y))$:
$$p(z|z_{0:n}) = \int p(z | \theta)p(\theta|z_{0:n}) d\theta$$
where
$$p …
0
votes
0
answers
91
views
Posterior predictive distribution example
I'd like use this information ($n$, $\bar{x}_1$, $s_1$, and $m$) to formulate closed-form expectations of $\bar{x}_2$ and $s_2$, and, after some research, it seems like posterior predictive distributions …
1
vote
0
answers
79
views
Acronyms to use for Bayesian posterior predictive distribution estimators
I am considering writing an article that discusses the Bayesian MMSE and MAP of the posterior predictive distribution. … I was wondering if there are acronyms that have been used so that instead of always saying: "The MMSE of the posterior predictive distribution..." …
0
votes
1
answer
216
views
Proving result about expectation under posterior predictive distribution
I am trying to figure out how to prove a result about the expectation of a random variable under the posterior predictive distribution, that may or may not be true. … expectation is taken under the posterior distribution. …
12
votes
2
answers
10k
views
Evaluate posterior predictive distribution in Bayesian linear regression
predictive distribution is analytic and is student t. … Is there an analytic form for the posterior predictive distribution in this case? Can I just plug my estimate of it into a multivariate student t? …