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A test (typically of distribution, independence, or goodness of fit), for the family of distributions use [chi-squared-distribution].
1
vote
K-S test correcting, or is a $\chi^2$ acceptable?
$60\%$ makes no sense. The chi -square test compares the observed frequency to the expect frequency under the assumptions of your normal model $N(3.825, 0.03770^2)$. The chi square distribution is ap …
4
votes
Chi square test on non-normal distributions
Normality is a requirement for the chi square test that a variance equals a specified value but there are many tests that are called chi-square because their asymptotic null distribution is chi-square …
3
votes
Accepted
Chi-squared vs Fisher's Exact Test w/ 5x6 contingency table & some cells <5?
There is a form of Fisher's test that is applicable to general rxc contingency tables. Use it or other alternatives to chi square in situations like yours where the chi square approximation is likely …
12
votes
Understanding Fisher's combined test
The Fisher combination test is intended to combine information from separate tests done on independent data sets in order to obtain power when the individual tests may not have sufficient power. The …
9
votes
Accepted
For chi-square on any 2 by X contingency table, should no more than 20% of the cells be les...
I am familiar with an earlier version of the book but I have not seen the specific discussion that you refer to. So I am not exactly sure what they are getting at but I think I have a pretty good ide …
2
votes
Statistics for gambling machine validation
For a fair game successive plays should be independent. It sounds like they are asking you to perform a test that consecutive results are uncorrelated. You could do this by pairing the data let $R_1, …
1
vote
When does a random test fail?
This is classical hypothesis testing. The null hypothesis state that the data are randomly placed in the categories. If the null hypothesis is true V will ASYMPTOTICALLY have the stated chi square d …
2
votes
Form of $\chi^2$ test
The usual chi square test would only have mi in the denominator not the sum. Chi square is an asymptotic distribution for the test statisitc and doesn't require any Gaussian assumption.
I don't think …
4
votes
Contingency tables: what tests to do and when?
I will try to address some of your questions as best as I can from my perspective. First the Fisher-Irwin Test is just another name for Fisher's exact test. Except for the fact that it is sometimes co …
2
votes
How can I show that for any $a > 0$, $\lim_{n\to \infty}P \left(\sum_{i=1}^n X_i^2\leq a\rig...
We note that since each $X_i$ has mean 0 and variance 1, $(\sum_i X_i^2)/n$ converges to 1 a.s.
But if
$$
\lim_{n\to\infty} \mathbb P\Big( \sum_i X_i^2 < a \Big) > 0 \,,
$$ then with positive probab …
1
vote
Which test to use to check if a possible confounder impacts a 0 / 1 result?
To answer 1 you can look for differences in proportions in the 2x2 contingency table. This can be done using Fisher's exact test or the approximate chi square test among others.
For 2 construct a 2x …
1
vote
Chi-squared test for nonlinear regression
There are three excellent books on nonlinear regression that are at the level of your interest. I don't know if they look at goodness of fit tests for the model though. Anyway one is Gallant
and …
3
votes
Accepted
How to determine if one fit is significantly better than a slightly different fit?
As Peter Flom suggests given your models you have a likelihood function and these information criteria can compare models based on their likelihood function with penalties for parameters used that can …
3
votes
Chi-squared and repeated measures
The pooling of litters for an individual set of parents seems reasonable to me. If the data could be put into a kxk contingency table and the male mice could be naturally paired with female mice a ge …
6
votes
Accepted
How do I get a $p$-value from the Cochran-Armitage trend test?
This is just a different definition of the statistic $T$. Call your statistic $T_1$ and the other $T_2$. Note the $T_2 = T_1/N$ and that is the reason that the variance of $T_2$ differs from $T_1$ b …