Search Results
Search type | Search syntax |
---|---|
Tags | [tag] |
Exact | "words here" |
Author |
user:1234 user:me (yours) |
Score |
score:3 (3+) score:0 (none) |
Answers |
answers:3 (3+) answers:0 (none) isaccepted:yes hasaccepted:no inquestion:1234 |
Views | views:250 |
Code | code:"if (foo != bar)" |
Sections |
title:apples body:"apples oranges" |
URL | url:"*.example.com" |
Saves | in:saves |
Status |
closed:yes duplicate:no migrated:no wiki:no |
Types |
is:question is:answer |
Exclude |
-[tag] -apples |
For more details on advanced search visit our help page |
a sequence of objects or individuals collected from a larger (possibly infinite) population or process.
1
vote
Probability density of the product of independent identically distributed random variables
This looks like a self-study question, so I will only give some hints:
To study the distribution of a product of independent random variables, you can turn it into a problem of sums, by taking logs. …
2
votes
Running regressions on subsamples: Include the variable on which the subsample is based in t...
If your income variable from the outset is categorical with values poor, vulnerable and non-poor, then after splitting the sample in three subsamples there is no variation left in that variable, so including … If you decide to include it, then the interpretation of the variable and its coefficiewnt will be different from in the full sample model: Now it differentiates by income within the "poor" group, say, …
5
votes
Bootstrapping as a way of learning about the population
If you want/need a new, different sample from the population the only way to get that is to sample from the population! … Its grounding, apart from its intuitive appeal, is in large sample theory, that is, approximations based on a large sample size. …
2
votes
Accepted
How can I get a sample of a product of two independent random variables?
Then to simulate a sample of independent realization of $Y$, simulate first independent realizations of $X_1$, then independent from that, a sample of independent realizations from $X_2$ and then use $ …
3
votes
Variance of Sample Mean for a Positively Correlated Sample
Let $X=(X_1, \dotsc, X_n)^T$ which has covariance matrix $\Sigma=\sigma^2 R$ where the correlation matrix $R$ has diagonal elements $R_{ii}=1$ and off-diagonals $R_{ij}=a, i\not = j$ (here $-\frac1{n- …
0
votes
Selecting a proportion mix from three respondent groups?
If you are using a random sample of people, how can you choose how many from each group? … But maybe you want to estimate a model from this sample (and retrospectively obtained demographic data), to use in future ... Maybe in future you really want to find the people in group 3. …
1
vote
Accepted
Finding Standard error of the sample mean by making multiple samples behave like a single one
The different subsamples come from interviewing a random sample of people, sampled independently from different locations, which are themselves a sample from the total population. … If that is zero, all the subpopulations have the same distribution, and we could really "treat the 10 subsamples like one large sample", otherwise we should not. …
2
votes
Why is each observation in a sample considered a random variable in linear regression?
In terms of your example, where $X$ is a person's weight, and there is a sample of $n$ persons, then $X_1$ is weight of first person in sample, $X_2$ is weight of second person in sample, and so on. …
3
votes
Accepted
Distribution of the sample mean of Poisson random variables
No, the sample mean of an independent sample from a Poisson distribution is NOT Poisson distributed. … But, the sum of the sample ($n$ times the mean) do have a Poisson distribution, and all wanted probabilities can be calculated from that. …
5
votes
Significance testing when the treatment group was only partially treated (an unknown set of ...
The R code used:
n <- 100 # "treatment" sample size
m <- 100 # control sample size
mu <- 10; sigma <- 3; delta <- 0.8
w <- 0.6 # fraction of treatment data really treated
# Simulating some data:
set.seed …
2
votes
Prevalence upper bound when no events are observed in sample
The general rule that people seem to use is to simply take $3/n$
(which in your case is 0.15%). This is sometimes called the "rule of three", and there are many questions here about this. (I do not …