Search Results
| Search type | Search syntax |
|---|---|
| Tags | [tag] |
| Exact | "words here" |
| Author |
user:1234 user:me (yours) |
| Score |
score:3 (3+) score:0 (none) |
| Answers |
answers:3 (3+) answers:0 (none) isaccepted:yes hasaccepted:no inquestion:1234 |
| Views | views:250 |
| Code | code:"if (foo != bar)" |
| Sections |
title:apples body:"apples oranges" |
| URL | url:"*.example.com" |
| Saves | in:saves |
| Status |
closed:yes duplicate:no migrated:no wiki:no |
| Types |
is:question is:answer |
| Exclude |
-[tag] -apples |
| For more details on advanced search visit our help page | |
Results tagged with independence
Search options answers only
not deleted
user 22228
Events (or random variables) are independent when information on some of them tells you nothing about the probability of occurrence (/ distribution) of the others. Please DO NOT use this tag for independent variable use [predictor] instead.
20
votes
If X and Y are uncorrelated, are X^2 and Y also uncorrelated?
Even if $\operatorname{Corr}(X,Y)=0$, not only is it possible that $X^2$ and $Y$ are correlated, but they may even be perfectly correlated, with $\operatorname{Corr}(X^2,Y)=1$:
> x <- c(-1,0,1); y <- …
- 23.9k
16
votes
Accepted
Probability of surviving an event three times
When you write "No extra variables, each incident is isolated and does not affect the subsequent", the mathematical word for this is that they are independent. And for independent events $A$ and $B$, …
- 23.9k
33
votes
Accepted
How does one find the mean of a sum of dependent variables?
Expectation (taking the mean) is a linear operator.
This means that, amongst other things, $\mathbb{E}(X + Y) = \mathbb{E}(X) + \mathbb{E}(Y)$ for any two random variables $X$ and $Y$ (for which the …
- 23.9k
18
votes
For which distributions does uncorrelatedness imply independence?
"Nevertheless if the two variables are normally distributed, then uncorrelatedness does imply independence" is a very common fallacy.
That only applies if they are jointly normally distributed. …
- 23.9k