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A description of a probability distribution which is related to the Laplace transform. Use also for its logarithm, the cumulant generating function.

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1 answer
80 views

Evaluating $E(x^{-1}). $

Could you please help me to prove the following equation: $$E(x^{-1})=\int_{0}^{\infty}M_{x}(-t)dt$$ Where $M_{x}(-t)$ is the moment-generating function. I think the following equation will be useful: …
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Accepted

Evaluating $E(x^{-1}). $

$$E\left(\frac{1}{x}\right)=\int_{-\infty}^{0}{e^{ux}du}=\int_{0}^{\infty}{e^{-ux}du}$$ $$E\left(\frac{1}{x}\right)=\int_{0}^{\infty}{x^{-1}f\left(x\right)dx=\int_{0}^{\infty}{\left(\int_{0}^{\infty}{ …
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0 votes
1 answer
432 views

Expected value of Y = (1/X) where X is Gamma Distribution [closed]

Let's suppose $$E\left(\frac{1}{x}\right)=\int_{0}^{\infty}{M_X(-t)dt}$$ Could you please help me to find $$E\left(\frac{1}{x}\right)$$ where $$X \sim\textrm{Gamma}(\alpha, \beta)$$ and $$E(X) = \alp …
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0 votes
1 answer
100 views

Limiting value of the moment generating function

Suppose that the discrete random variable $X_{n}$has a geometric distribution given by $$f_{X_n}(x_n)=P_n{(1-P_n)}^{x_n}$$ where $$x_n={0,1,2,3,}$$ and $$P_n\ =\ \frac{\lambda}{n}$$ for $0<\lambda<n$. …
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