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Techniques for analyzing the relationship between one (or more) "dependent" variables and "independent" variables.
1
vote
How do I get $\beta$ from $b$ in a simple regression?
To get $\beta$ instead of $b$, all you have to do is standardize your $x$ and your $y$ are run a regression of the standardized $y$ on the standardized $x$. … Then run the regression:$$\tilde{y}=\tilde{x}b+u$$
and you will estimate the slope paramter in standard deviation units. …
1
vote
Difference between the effect and the contribution of a regressor
I think I figured the answer out. Ultimately, I am trying to compare the partial $R^{2}$
to the coefficient. They are in some ways related. Consider we have a model:$$y=x\beta+\epsilon$$
where $x$
…
0
votes
1
answer
59
views
Estimator that maximizes t-value
Consider the linear regression model:$$y=\beta_{0}+\beta_{1}x+u$$
The OLS estimators minimze the squared sum of residuals. …
2
votes
1
answer
177
views
Difference between the effect and the contribution of a regressor
Consider that we have the following time series of observations: $C_{t},I_{t},G_{t},X_{t}-M_{t}$
Now, $Y_{t}$
is defined as:$$Y_{t}=C_{t}+I_{t}+G_{t}+X_{t}-M_{t}$$
If we were to run a regression of …
2
votes
5
answers
174
views
Constant Variance restrictive as a general rule?
Think of a linear regression model:
$$
Y=X\beta+\epsilon
$$
where $\epsilon|X\sim N\left(0,\sigma^{2}\right)$. The vector of
parameters $\beta$ can be consistenly estimated by OLS. …
1
vote
0
answers
504
views
Correlation between regressors and error term
I have a question regarding linear regression that has been confusing me for some time. … Consider the linear regression model in matrix notation $$Y=X\beta+\epsilon$$
Consider now the OLS estimator that can be derived from the moment condition:$$E[X'\epsilon]=0$$
Now, we can write the vector …
1
vote
Pooled data in regression analysis
Pooled OLS regressions in the case of Panel Data are usually frowned upon.First, if the conditional exogeneity condition holds, that is:
$$
E[(\alpha_{i}+u_{it}|X_{it})]=0
$$
holds, then you might as …
0
votes
Does this P-P plot indicate a violation of the normality assumption?
There are formal tests for normality- in particular the Jarque-Bera/Skewness-Kurtosis type tests.
1
vote
Regression - non linear transformation confusion
I got it after thinking it through. Of course, in both cases, the marginal effect of $x_{1}$
is the same for a given value of $x_{1}$
and $x_{2.}$
The difference is that the second model includes s …
0
votes
0
answers
49
views
Linear Regression
Consider the regression model:$$y=x\beta+u$$
Let us take expectations:$$E[y]=E[x\beta+u]=E[x\beta]$$
by linearity of the expectations operator and $E[u]=0$
. …
1
vote
1
answer
1k
views
Law of Iterated Expectations in Linear Regression
Consider the following model:$$y=x\beta+u$$
Now, let us take conditional expectations, assuming conditional exogeneity, such that $$E[u|x]=0$$
$$E[y|x]=\beta E[x|x]=\beta x$$
By the Law of Iterated …
1
vote
Using estimated parameters as dependent variables
As the RHS variables are generated by OLS, they are actually "generated regressors". It is perfectly fine to estimate the model by OLS, but you have to adjust standard errors. The classic paper by Pag …
0
votes
0
answers
66
views
Herfindahl Hirschman Indices
Now, I wish to run a
regression, say of ${HH}_{t}$ (or the HH index on time $T)$ on a particular
set of world characteristcs, call it $X_{Wt}$. … The regression is:
$$
{HH}_{t}=\alpha+\beta X_{Wt}+\epsilon_{t}
$$
Now, in the above, the problem is that every year, the total number
of countries is changing. …
1
vote
1
answer
97
views
Regression - non linear transformation confusion
Consider a regression model:$$y=x_{1}\beta_{1}+x_{2}\beta_{2}+u$$
Now, consider a different regression model:$$y=\frac{x_{1}}{x_{2}}\gamma_{1}+x_{2}\gamma_{2}+v$$
Of course, in the second model, the … I mean whenever I think of linear regression, I always think of it as holding the value of an included regressor constant. …
8
votes
1
answer
820
views
Non Linear Endogeneity
Consider the following Linear Regression Model. …