Iago Carvalho
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1 answers
1 votes
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Statistical validaty of heuristic labelling
1 votes

you can do that as you want. I was thinking this will require manual validation of a sample In order to evaluate your heuristic results, you really need a manner to correctly classifies your data....

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1 answers
0 votes
57 views
Statistical Analysis of 3 groups(parameterisation of same algorithm) under the same dataset: non-repeated measures or repeated-measures?
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1 votes

Since you are evaluating more than two treatments (parametrizations of your algorithm), you should use a repeated measures test blocked by subject, i.e., Friedman's test. For a post-hoc procedure, I (...

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1 answers
0 votes
208 views
How to arrange my data for Friedman's test
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I think you have a small error when building the table used to the Friedman's test. Since you have 4 replicates, you may need to consider each of them individually (and not summarize the average ...

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1 answers
1 votes
417 views
How to run Friedman test correctly across three sets of questionnaire data divided into sub-groups?
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let's solve your question in parts. First of all, if you have three prototypes, then we can consider that you have three treatments. For each prototype, you collected the responses of individuals ...

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2 answers
2 votes
919 views
Friedman's test or Kruskal-Wallis?
1 votes

Given your structure (blocked by subject, paired or repeated data measures), you can use the Friedman's test. Furthermore, if Friedman's test shows that there are significant differences among your ...

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1 answers
1 votes
1k views
Which is right to perform a Tukey post hoc in R?
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There are a few basic differences among your tests. Tests 1. (glht) and 2. (TukeyHSD) are the same. However, the glht test employs a p-value adjustment method (described as the simple-step method), ...

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1 answers
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719 views
How to obtain the results of the Nemenyi post-hoc test in a table showing grouped pairs?
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1 votes

After a little more of research, I found a R code that solved this question. However, I still don't know how it works. It is possible to use the multcompLetters function of the multcompView package ...

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1 answers
0 votes
502 views
Tukey-Kramer or Nemenyi following Friedman
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In the package it says that Tukey-Kramer (Nemenyi). So the question here is, are Tukey-Kramer and Nemenyi are the same test? I read the package description. In the R package, it looks like that both ...

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3 answers
1 votes
3k views
Paired samples t test in Python
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3 votes

the function ttost is not a t-test and therefore is not suitable for your purposes. The TTOST is a test of non-equivalence. It employes two one-sided t-tests in order to verify if both samples are ...

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1 answers
0 votes
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Correction needed for an non-parametric Anova?
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The Friedman's is a non-parametric rank-sum test. In other words, it ranks the results of each subject across all evaluated conditions. Therefore, any correction applied to your data will not change ...

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