Timeline for Probability estimation of minesweeper undecidable choices
Current License: CC BY-SA 3.0
10 events
when toggle format | what | by | license | comment | |
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Aug 12, 2015 at 17:16 | answer | added | Siwel | timeline score: 3 | |
Jul 15, 2014 at 4:33 | answer | added | parvij | timeline score: 1 | |
Jul 14, 2014 at 23:48 | history | tweeted | twitter.com/#!/StackStats/status/488832545313009664 | ||
Jul 14, 2014 at 20:46 | comment | added | caub | the total in this situation near the end of the game yes, it is well known: 2m+n=number of remaining pairs=1/2*number of remaining blocks, sorry I wasn't clear | |
Jul 14, 2014 at 20:36 | comment | added | whuber♦ | Although it's not needed in your specific example, it can be needed in general settings. It sounds like you are stipulating that the total is known. | |
Jul 14, 2014 at 20:35 | comment | added | caub | that's not needed, you know there's a mine in each pair of block, so with my notations, it remains 2m+n mines | |
Jul 14, 2014 at 18:59 | comment | added | whuber♦ | Do you know the total number of mines in the game or not? | |
Jul 14, 2014 at 17:18 | history | edited | caub | CC BY-SA 3.0 |
edited title
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Jul 14, 2014 at 17:05 | history | edited | caub | CC BY-SA 3.0 |
deleted 161 characters in body
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Jul 14, 2014 at 16:56 | history | asked | caub | CC BY-SA 3.0 |