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Jul 31, 2014 at 23:32 vote accept FredikLAa
Jul 31, 2014 at 23:29 comment added FredikLAa Thanks, whuber, very much appreciated. Just to be 100 % sure, you say that $$f(\alpha_0 +\alpha_1 z_1 + \cdots + \alpha_d z_d)=f(\beta_0 + \beta_1 x_1 + \cdots + \beta_d x_d),$$ since unique minimum is assumed, $ \alpha_0 +\alpha_1 z_1 + \cdots + \alpha_d z_d=\beta_0 + \beta_1 x_1 + \cdots + \beta_d x_d$ and you then identify the different coefficients "term-wise" (coefficients in front of the $x_1$s must be the same, etc)?
Jul 31, 2014 at 21:27 history answered whuber CC BY-SA 3.0