Skip to main content
2 events
when toggle format what by license comment
Aug 12, 2014 at 1:37 comment added yong Hmmm, so what would be the correct equation for $p(x \mid y)$ that has a $p(x)$ or $p(y)$ term in it? $p(x, y, \epsilon) = 1$ iff $x + y = \epsilon$, right? I'm not seeing how it's helpful?
Aug 12, 2014 at 1:28 history answered Memming CC BY-SA 3.0