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Jan 26, 2017 at 20:29 history edited amoeba
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Dec 19, 2014 at 6:01 vote accept the_deuce
Dec 10, 2014 at 20:49 comment added whuber It's still not quite right. When $\alpha\lt 1/2$ and $0\lt k \lt 1$, both $Z_{k\alpha}$ and $Z_{(1-k)\alpha}$ are negative and therefore the interval you have written is empty! The meaning of your question is evident only from the intended conclusion, which implies the optimal interval is given by $[\bar{X}+Z_{\alpha/2} \sigma/\sqrt{n}, \bar{X}+Z_{1-\alpha/2} \sigma/\sqrt{n}]$. (There are many other ways to write this interval, since $Z_\beta = -Z_{1-\beta}$ for all $0\lt \beta \lt 1$, but your expression is not among the correct ones.)
Dec 10, 2014 at 20:37 history edited the_deuce CC BY-SA 3.0
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Dec 10, 2014 at 18:38 answer added whuber timeline score: 6
Dec 10, 2014 at 17:52 comment added whuber You probably meant to write "...$Z_{(1-k)\alpha}$...". The signs in front of the $Z_{*}$ are also problematic.
Dec 10, 2014 at 7:51 history edited gung - Reinstate Monica CC BY-SA 3.0
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Dec 10, 2014 at 7:45 review First posts
Dec 10, 2014 at 7:51
Dec 10, 2014 at 7:41 history asked the_deuce CC BY-SA 3.0