Timeline for How to simulate a system where "the failure probability per week is 3.5%"?
Current License: CC BY-SA 3.0
5 events
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| Jul 18, 2015 at 23:56 | comment | added | DWin |
Can you check your math? I get lambda=-log(1-0.035)/7 and so lambda = 0.00509
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| Feb 11, 2015 at 18:54 | history | bounty ended | Alessandro Jacopson | ||
| Feb 11, 2015 at 18:54 | vote | accept | Alessandro Jacopson | ||
| Feb 5, 2015 at 4:51 | comment | added | Cam.Davidson.Pilon | This also works well because of the forgetfulness property of the exponential: given you have survived this last, the probability you fail this next week is equal to that of last week, i.e. your survival is independent of how long you have survived for. (A consequence of a constant hazard rate). This means that if we start with $N$ machines, there will still always be 3.5% failure each week (on average). | |
| Feb 5, 2015 at 0:48 | history | answered | Sven | CC BY-SA 3.0 |