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Feb 12, 2015 at 23:37 comment added EngrStudent @whuber, the OP wants rank less than M or N. If they were to reduce through both setting low magnitude eigenvalues to zero and then rotating to whatever was left - the rank of the column-space would be the number of non-zero elements in the diagonal of the eigenvalue matrix.
Feb 12, 2015 at 22:10 comment added whuber The problem statement treats rows and columns perfectly symmetrically. The appearance of different recommendations for processing them is therefore quite surprising.
Feb 12, 2015 at 22:01 comment added amoeba That's some interesting suggestions in your edit. +1. However, even though I am not sure what exactly OP was asking about, it seems that he/she had yet another thing in mind...
Feb 12, 2015 at 21:31 history edited EngrStudent CC BY-SA 3.0
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Feb 12, 2015 at 16:00 history edited EngrStudent CC BY-SA 3.0
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Feb 12, 2015 at 15:36 comment added amoeba I don't see how this answers the question. Your procedure will not result in removing "some of the rows or columns", as asked by the OP.
Feb 12, 2015 at 15:25 history answered EngrStudent CC BY-SA 3.0