Timeline for conditional density wrt lebesgue measure
Current License: CC BY-SA 3.0
9 events
when toggle format | what | by | license | comment | |
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Feb 12, 2015 at 19:02 | comment | added | Zen | No: $\int_{\mathbb{R}} f_{X,Y}(x,y)d\lambda(y) = f_X(x)$, the marginal density of $X$. | |
Feb 12, 2015 at 18:43 | comment | added | user2016445 | oh sry my mistake :), $\int_{\mathbb{R}} f_{X,Y}(x,y)d\lambda(y) = 1$ it is true so everythin is fine. thank you it solved my problem. | |
Feb 12, 2015 at 18:19 | comment | added | Zen | I wrote four equalities. Which one "doesn't hold"? | |
Feb 12, 2015 at 17:26 | comment | added | user2016445 | that is not true, this holds: $\int_A \mathbb{P}(X \in dx) \int_B f_{Y|X}(x,y)\lambda(dy) = \int_{A \times B}f(x,y)\lambda^2(dx,dy)$ | |
Feb 12, 2015 at 16:38 | comment | added | Zen | $P(X\in A) = P(X\in A, Y\in\mathbb{R}) = \int_{A\times\mathbb{R}} f_{X,Y}(x,y)\,d\lambda^2(x,y) = \int_A\left(\int_\mathbb{R} f_{X,Y}(x,y)\,d\lambda(y)\right)d\lambda(x) = \int_A f_X(x)\,d\lambda(x)$ | |
Feb 12, 2015 at 16:37 | comment | added | Zen | Fubini: en.wikipedia.org/wiki/… | |
Feb 12, 2015 at 16:24 | history | edited | user2016445 | CC BY-SA 3.0 |
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Feb 12, 2015 at 15:59 | history | edited | user2016445 | CC BY-SA 3.0 |
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Feb 12, 2015 at 15:27 | history | asked | user2016445 | CC BY-SA 3.0 |