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When $x$ has a causal effect on $y$, the elasticity is

the ratio of the percentage change in one variable to the percentage change in another variable

(Wikipedia).

When $x$ is changed to $x + dx$, causing $y$ to change to $y+dy$, the percentage changes are $100 dx / x$ and $100 dy / y$, respectively. Their ratio is

$$\frac{100\, dy/y}{100\, dx/x} = \frac{dy}{dx} / \frac{y}{x}.$$

Letting $y$ stand for the fitted value at $x$, we may compute

$$y = (\beta_0 + \beta_1\sqrt{x} )^2$$

and

$$\frac{dy}{dx} = \frac{2 \sqrt{y} \beta_1 }{2\sqrt{x}} = \beta_1 \frac{\sqrt{y}}{\sqrt{x}}.$$

Consequently the elasticity is

$$\beta_1 \frac{\sqrt{y}}{\sqrt{x}} / \frac{y}{x} = \beta_1 \frac{\sqrt{x}}{\sqrt{y}} = \frac{\beta_1\sqrt{x}}{\beta_0 + \beta_1 \sqrt{x} }.$$

When analyzing data, you can only estimate the elasticity using estimates $b_0$ and $b_1$ instead of the true (but unknown) coefficients $\beta_0$ and $\beta_1$. Therefore the estimated elasticity at any point $x_0$ will be

$$\frac{b_1\sqrt{x_0}}{b_0 + b_1 \sqrt{x_0} }.$$


There are many ways to compute confidence intervals for those estimates. In the absence of the data--knowing only the variance-covariance matrix of the estimates--use the Delta methodDelta method. When fitting using another procedure, such as Maximum Likelihood, you might be able to obtain confidence limits directly (such as by profiling the likelihood for a fixed $x_0$).

Note that the estimated elasticity is not constant unless $b_0=0$, or at least (approximately) when $|b_0| \ll |b_1 x_0|$.


As a double-check, consider the limiting case $\beta_0=0$. The original model for the fit

$$\sqrt{y} = \beta_1 \sqrt{x}, $$

can be rewritten

$$\log(y) = \log(\beta_1^2) + \log(x).$$

In a log-log model, the elasticity is the coefficient of $\log(x)$, here shown to be $1$. Indeed,

$$\frac{\beta_1 \sqrt{x}}{\beta_0 + \beta_1 \sqrt{x}} = \frac{\beta_1\sqrt{x}}{\beta_1 \sqrt{x}} = 1$$

agrees with that.

When $x$ has a causal effect on $y$, the elasticity is

the ratio of the percentage change in one variable to the percentage change in another variable

(Wikipedia).

When $x$ is changed to $x + dx$, causing $y$ to change to $y+dy$, the percentage changes are $100 dx / x$ and $100 dy / y$, respectively. Their ratio is

$$\frac{100\, dy/y}{100\, dx/x} = \frac{dy}{dx} / \frac{y}{x}.$$

Letting $y$ stand for the fitted value at $x$, we may compute

$$y = (\beta_0 + \beta_1\sqrt{x} )^2$$

and

$$\frac{dy}{dx} = \frac{2 \sqrt{y} \beta_1 }{2\sqrt{x}} = \beta_1 \frac{\sqrt{y}}{\sqrt{x}}.$$

Consequently the elasticity is

$$\beta_1 \frac{\sqrt{y}}{\sqrt{x}} / \frac{y}{x} = \beta_1 \frac{\sqrt{x}}{\sqrt{y}} = \frac{\beta_1\sqrt{x}}{\beta_0 + \beta_1 \sqrt{x} }.$$

When analyzing data, you can only estimate the elasticity using estimates $b_0$ and $b_1$ instead of the true (but unknown) coefficients $\beta_0$ and $\beta_1$. Therefore the estimated elasticity at any point $x_0$ will be

$$\frac{b_1\sqrt{x_0}}{b_0 + b_1 \sqrt{x_0} }.$$


There are many ways to compute confidence intervals for those estimates. In the absence of the data--knowing only the variance-covariance matrix of the estimates--use the Delta method. When fitting using another procedure, such as Maximum Likelihood, you might be able to obtain confidence limits directly (such as by profiling the likelihood for a fixed $x_0$).

Note that the estimated elasticity is not constant unless $b_0=0$, or at least (approximately) when $|b_0| \ll |b_1 x_0|$.


As a double-check, consider the limiting case $\beta_0=0$. The original model for the fit

$$\sqrt{y} = \beta_1 \sqrt{x}, $$

can be rewritten

$$\log(y) = \log(\beta_1^2) + \log(x).$$

In a log-log model, the elasticity is the coefficient of $\log(x)$, here shown to be $1$. Indeed,

$$\frac{\beta_1 \sqrt{x}}{\beta_0 + \beta_1 \sqrt{x}} = \frac{\beta_1\sqrt{x}}{\beta_1 \sqrt{x}} = 1$$

agrees with that.

When $x$ has a causal effect on $y$, the elasticity is

the ratio of the percentage change in one variable to the percentage change in another variable

(Wikipedia).

When $x$ is changed to $x + dx$, causing $y$ to change to $y+dy$, the percentage changes are $100 dx / x$ and $100 dy / y$, respectively. Their ratio is

$$\frac{100\, dy/y}{100\, dx/x} = \frac{dy}{dx} / \frac{y}{x}.$$

Letting $y$ stand for the fitted value at $x$, we may compute

$$y = (\beta_0 + \beta_1\sqrt{x} )^2$$

and

$$\frac{dy}{dx} = \frac{2 \sqrt{y} \beta_1 }{2\sqrt{x}} = \beta_1 \frac{\sqrt{y}}{\sqrt{x}}.$$

Consequently the elasticity is

$$\beta_1 \frac{\sqrt{y}}{\sqrt{x}} / \frac{y}{x} = \beta_1 \frac{\sqrt{x}}{\sqrt{y}} = \frac{\beta_1\sqrt{x}}{\beta_0 + \beta_1 \sqrt{x} }.$$

When analyzing data, you can only estimate the elasticity using estimates $b_0$ and $b_1$ instead of the true (but unknown) coefficients $\beta_0$ and $\beta_1$. Therefore the estimated elasticity at any point $x_0$ will be

$$\frac{b_1\sqrt{x_0}}{b_0 + b_1 \sqrt{x_0} }.$$


There are many ways to compute confidence intervals for those estimates. In the absence of the data--knowing only the variance-covariance matrix of the estimates--use the Delta method. When fitting using another procedure, such as Maximum Likelihood, you might be able to obtain confidence limits directly (such as by profiling the likelihood for a fixed $x_0$).

Note that the estimated elasticity is not constant unless $b_0=0$, or at least (approximately) when $|b_0| \ll |b_1 x_0|$.


As a double-check, consider the limiting case $\beta_0=0$. The original model for the fit

$$\sqrt{y} = \beta_1 \sqrt{x}, $$

can be rewritten

$$\log(y) = \log(\beta_1^2) + \log(x).$$

In a log-log model, the elasticity is the coefficient of $\log(x)$, here shown to be $1$. Indeed,

$$\frac{\beta_1 \sqrt{x}}{\beta_0 + \beta_1 \sqrt{x}} = \frac{\beta_1\sqrt{x}}{\beta_1 \sqrt{x}} = 1$$

agrees with that.

Clarified some phrases.
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whuber
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When $x$ has a causal effect on $y$,When $x$ has a causal effect on $y$, the elasticity is

the ratio of the percentage change in one variable to the percentage change in another variable

(Wikipedia).

The percentage changes whenWhen $x$ is changed to $x + dx$, causing a change in $y$ to change to $y+dy$, the percentage changes are $100 dx / x$ and $100 dy / y$, respectively. The Their ratio is

$$\frac{100 dy/y}{100 dx/x} = \frac{dy}{dx} / \frac{y}{x}.$$$$\frac{100\, dy/y}{100\, dx/x} = \frac{dy}{dx} / \frac{y}{x}.$$

Letting $y$ stand for the fitted value at $x$, we may compute

$$y = (\beta_0 + \beta_1\sqrt{x} )^2$$

and

$$\frac{dy}{dx} = \frac{2 \sqrt{y} \beta_1 }{2\sqrt{x}} = \beta_1 \frac{\sqrt{y}}{\sqrt{x}}.$$

Consequently the elasticity is

$$\beta_1 \frac{\sqrt{y}}{\sqrt{x}} / \frac{y}{x} = \beta_1 \frac{\sqrt{x}}{\sqrt{y}} = \frac{\beta_1\sqrt{x}}{\beta_0 + \beta_1 \sqrt{x} }.$$

YouWhen analyzing data, you can only estimateestimate the elasticity from data, using estimates $b_0$ and $b_1$ instead of the true (but unknown) coefficients $\beta_0$ and $\beta_1$. The estimated elasticity at any point Therefore $x_0$ will bethe estimated elasticity at any point $x_0$ will be

$$\frac{b_1\sqrt{x_0}}{b_0 + b_1 \sqrt{x_0} }.$$

 

There are many ways to compute confidence intervals for those estimates. In the absence of the data--knowing only the variance-covariance matrix of the estimates--use the Delta method. When fitting using another procedure, such as Maximum Likelihood, you might be able to obtain confidence limits directly (such as by profiling the likelihood for a fixed $x_0$).

Note that the estimated elasticity is not constant unless $b_0=0$, or at least (approximately) when $|b_0| \ll |b_1 x_0|$.


As a double-check,As a double-check, consider the limiting case $\beta_0=0$. The original model for the fit

$$\sqrt{y} = \beta_1 \sqrt{x}, $$

can be rewritten

$$\log(y) = \log(\beta_1^2) + \log(x).$$

In a log-log model, the elasticity is the coefficient of $\log(x)$, here shown to be $1$. Indeed,

$$\frac{\beta_1 \sqrt{x}}{\beta_0 + \beta_1 \sqrt{x}} = \frac{\beta_1\sqrt{x}}{\beta_1 \sqrt{x}} = 1$$

agrees with that.

When $x$ has a causal effect on $y$, the elasticity is

the ratio of the percentage change in one variable to the percentage change in another variable

(Wikipedia).

The percentage changes when $x$ is changed to $x + dx$, causing a change in $y$ to $y+dy$, are $100 dx / x$ and $100 dy / y$, respectively. The ratio is

$$\frac{100 dy/y}{100 dx/x} = \frac{dy}{dx} / \frac{y}{x}.$$

Letting $y$ stand for the fitted value at $x$, we compute

$$y = (\beta_0 + \beta_1\sqrt{x} )^2$$

and

$$\frac{dy}{dx} = \frac{2 \sqrt{y} \beta_1 }{2\sqrt{x}} = \beta_1 \frac{\sqrt{y}}{\sqrt{x}}.$$

Consequently the elasticity is

$$\beta_1 \frac{\sqrt{y}}{\sqrt{x}} / \frac{y}{x} = \beta_1 \frac{\sqrt{x}}{\sqrt{y}} = \frac{\beta_1\sqrt{x}}{\beta_0 + \beta_1 \sqrt{x} }.$$

You can only estimate the elasticity from data, using estimates $b_0$ and $b_1$ instead of $\beta_0$ and $\beta_1$. The estimated elasticity at any point $x_0$ will be

$$\frac{b_1\sqrt{x_0}}{b_0 + b_1 \sqrt{x_0} }.$$

There are many ways to compute confidence intervals for those estimates. In the absence of the data--knowing only the variance-covariance matrix of the estimates--use the Delta method. When fitting using another procedure, such as Maximum Likelihood, you might be able to obtain confidence limits directly (such as by profiling the likelihood for a fixed $x_0$).

Note that the estimated elasticity is not constant unless $b_0=0$, or at least (approximately) when $|b_0| \ll |b_1 x_0|$.


As a double-check, consider the limiting case $\beta_0=0$. The original model for the fit

$$\sqrt{y} = \beta_1 \sqrt{x}, $$

can be rewritten

$$\log(y) = \log(\beta_1^2) + \log(x).$$

In a log-log model, the elasticity is the coefficient of $\log(x)$, here shown to be $1$. Indeed,

$$\frac{\beta_1 \sqrt{x}}{\beta_0 + \beta_1 \sqrt{x}} = \frac{\beta_1\sqrt{x}}{\beta_1 \sqrt{x}} = 1$$

agrees with that.

When $x$ has a causal effect on $y$, the elasticity is

the ratio of the percentage change in one variable to the percentage change in another variable

(Wikipedia).

When $x$ is changed to $x + dx$, causing $y$ to change to $y+dy$, the percentage changes are $100 dx / x$ and $100 dy / y$, respectively. Their ratio is

$$\frac{100\, dy/y}{100\, dx/x} = \frac{dy}{dx} / \frac{y}{x}.$$

Letting $y$ stand for the fitted value at $x$, we may compute

$$y = (\beta_0 + \beta_1\sqrt{x} )^2$$

and

$$\frac{dy}{dx} = \frac{2 \sqrt{y} \beta_1 }{2\sqrt{x}} = \beta_1 \frac{\sqrt{y}}{\sqrt{x}}.$$

Consequently the elasticity is

$$\beta_1 \frac{\sqrt{y}}{\sqrt{x}} / \frac{y}{x} = \beta_1 \frac{\sqrt{x}}{\sqrt{y}} = \frac{\beta_1\sqrt{x}}{\beta_0 + \beta_1 \sqrt{x} }.$$

When analyzing data, you can only estimate the elasticity using estimates $b_0$ and $b_1$ instead of the true (but unknown) coefficients $\beta_0$ and $\beta_1$. Therefore the estimated elasticity at any point $x_0$ will be

$$\frac{b_1\sqrt{x_0}}{b_0 + b_1 \sqrt{x_0} }.$$

 

There are many ways to compute confidence intervals for those estimates. In the absence of the data--knowing only the variance-covariance matrix of the estimates--use the Delta method. When fitting using another procedure, such as Maximum Likelihood, you might be able to obtain confidence limits directly (such as by profiling the likelihood for a fixed $x_0$).

Note that the estimated elasticity is not constant unless $b_0=0$, or at least (approximately) when $|b_0| \ll |b_1 x_0|$.


As a double-check, consider the limiting case $\beta_0=0$. The original model for the fit

$$\sqrt{y} = \beta_1 \sqrt{x}, $$

can be rewritten

$$\log(y) = \log(\beta_1^2) + \log(x).$$

In a log-log model, the elasticity is the coefficient of $\log(x)$, here shown to be $1$. Indeed,

$$\frac{\beta_1 \sqrt{x}}{\beta_0 + \beta_1 \sqrt{x}} = \frac{\beta_1\sqrt{x}}{\beta_1 \sqrt{x}} = 1$$

agrees with that.

Source Link
whuber
  • 333.6k
  • 63
  • 792
  • 1.3k

When $x$ has a causal effect on $y$, the elasticity is

the ratio of the percentage change in one variable to the percentage change in another variable

(Wikipedia).

The percentage changes when $x$ is changed to $x + dx$, causing a change in $y$ to $y+dy$, are $100 dx / x$ and $100 dy / y$, respectively. The ratio is

$$\frac{100 dy/y}{100 dx/x} = \frac{dy}{dx} / \frac{y}{x}.$$

Letting $y$ stand for the fitted value at $x$, we compute

$$y = (\beta_0 + \beta_1\sqrt{x} )^2$$

and

$$\frac{dy}{dx} = \frac{2 \sqrt{y} \beta_1 }{2\sqrt{x}} = \beta_1 \frac{\sqrt{y}}{\sqrt{x}}.$$

Consequently the elasticity is

$$\beta_1 \frac{\sqrt{y}}{\sqrt{x}} / \frac{y}{x} = \beta_1 \frac{\sqrt{x}}{\sqrt{y}} = \frac{\beta_1\sqrt{x}}{\beta_0 + \beta_1 \sqrt{x} }.$$

You can only estimate the elasticity from data, using estimates $b_0$ and $b_1$ instead of $\beta_0$ and $\beta_1$. The estimated elasticity at any point $x_0$ will be

$$\frac{b_1\sqrt{x_0}}{b_0 + b_1 \sqrt{x_0} }.$$

There are many ways to compute confidence intervals for those estimates. In the absence of the data--knowing only the variance-covariance matrix of the estimates--use the Delta method. When fitting using another procedure, such as Maximum Likelihood, you might be able to obtain confidence limits directly (such as by profiling the likelihood for a fixed $x_0$).

Note that the estimated elasticity is not constant unless $b_0=0$, or at least (approximately) when $|b_0| \ll |b_1 x_0|$.


As a double-check, consider the limiting case $\beta_0=0$. The original model for the fit

$$\sqrt{y} = \beta_1 \sqrt{x}, $$

can be rewritten

$$\log(y) = \log(\beta_1^2) + \log(x).$$

In a log-log model, the elasticity is the coefficient of $\log(x)$, here shown to be $1$. Indeed,

$$\frac{\beta_1 \sqrt{x}}{\beta_0 + \beta_1 \sqrt{x}} = \frac{\beta_1\sqrt{x}}{\beta_1 \sqrt{x}} = 1$$

agrees with that.