Timeline for Mean and variance of a Beta distribution with $\alpha \ge 1$ or $\beta \ge 1$?
Current License: CC BY-SA 3.0
12 events
| when toggle format | what | by | license | comment | |
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| May 27, 2023 at 15:19 | comment | added | Henry | related: stats.stackexchange.com/questions/105029/… | |
| May 4, 2015 at 11:49 | vote | accept | a06e | ||
| Mar 21, 2015 at 15:46 | history | tweeted | twitter.com/#!/StackStats/status/579308170688012288 | ||
| Mar 20, 2015 at 22:16 | answer | added | whuber♦ | timeline score: 7 | |
| Mar 20, 2015 at 21:29 | answer | added | Alecos Papadopoulos | timeline score: 2 | |
| Mar 20, 2015 at 18:45 | history | edited | a06e | CC BY-SA 3.0 |
deleted 113 characters in body; edited title
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| Mar 20, 2015 at 18:21 | comment | added | whuber♦ | Thank you for the clarification. I have taken the liberty of correcting your definition by inserting the word "segment". Otherwise (in the form originally stated) your definition would not hold for any distribution. | |
| Mar 20, 2015 at 18:20 | history | edited | whuber♦ | CC BY-SA 3.0 |
added 8 characters in body
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| Mar 20, 2015 at 18:13 | comment | added | a06e | @whuber See edit. | |
| Mar 20, 2015 at 18:13 | history | edited | a06e | CC BY-SA 3.0 |
added 128 characters in body; edited title
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| Mar 20, 2015 at 17:33 | comment | added | whuber♦ | Please explain what you mean by a "distribution to be convex." You probably need to restrict the convexity to the support of the distribution function (for otherwise no distribution function is convex). But are you referring to its density function, cumulative density, or perhaps something else? | |
| Mar 20, 2015 at 17:03 | history | asked | a06e | CC BY-SA 3.0 |