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Jul 26, 2015 at 7:28 comment added Ehsan M. Kermani Right, that was shown in the paper referenced above.
Jul 26, 2015 at 5:34 comment added Glen_b @Ehsan The mean of the distribution is in fact exactly 25. In the symmetric case (boundaries evenly spaced either side of the start position and constant probability 0.5), it's the square of the number of spaces from the start to the absorbing barrier.
Jul 26, 2015 at 2:35 comment added Ehsan M. Kermani Thank you. Right, that's the same game as the famous Gambler's ruin problem, but with different objective. I was hoping to find a better modeling of the problem, perhaps using random walks and seeing why the mean (in this case) should be around 25, etc. I guess, the referenced paper might answer those questions.
Jul 26, 2015 at 2:26 vote accept Ehsan M. Kermani
Jul 26, 2015 at 0:57 history edited ltronneberg CC BY-SA 3.0
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Jul 26, 2015 at 0:52 history answered ltronneberg CC BY-SA 3.0