Timeline for Finding pattern from sparse matrix
Current License: CC BY-SA 3.0
15 events
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| May 23, 2017 at 12:39 | history | edited | CommunityBot |
replaced http://stackoverflow.com/ with https://stackoverflow.com/
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| Sep 8, 2015 at 9:59 | vote | accept | Kavipriya | ||
| Sep 8, 2015 at 9:59 | |||||
| Jul 31, 2015 at 4:59 | comment | added | Kavipriya | I am sorry. I am not supposed to share the data. Thanks for your help. | |
| Jul 29, 2015 at 12:49 | comment | added | Digio | PS: Feel free to share your data if you want. | |
| Jul 29, 2015 at 10:25 | history | edited | Digio | CC BY-SA 3.0 |
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| Jul 29, 2015 at 10:07 | history | edited | Digio | CC BY-SA 3.0 |
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| Jul 29, 2015 at 9:19 | vote | accept | Kavipriya | ||
| Sep 8, 2015 at 9:58 | |||||
| Jul 28, 2015 at 16:08 | history | edited | Digio | CC BY-SA 3.0 |
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| Jul 28, 2015 at 15:27 | comment | added | Digio | After some thought I believe you should still model your scenario as a graph problem. You could transform your nm time-series matrix into a nn similarity matrix which will represent an undirected weighted graph. I'll update my answer with this idea. | |
| Jul 28, 2015 at 6:45 | comment | added | Kavipriya | I updated my question itself. Sorry for that. It will be nice if you help. Thanks! | |
| Jul 28, 2015 at 5:53 | comment | added | Digio | Well that was important missing information. I'll need to update my answer, and by update I mean completely rewrite. | |
| Jul 28, 2015 at 5:48 | comment | added | Kavipriya | Each columns represent each action. Each row represents time. The data is collected for every 15min. I want to find how each action is dependent on another action. | |
| Jul 28, 2015 at 5:26 | comment | added | Digio | If it's not square then what do you have on the columns? How would you say that an action affects another action if it's not square? | |
| Jul 28, 2015 at 5:19 | comment | added | Kavipriya | Thanks! But my matrix is not square. It is 2lakh x 60 dimension. How can I interpret this as a graph? | |
| Jul 27, 2015 at 15:14 | history | answered | Digio | CC BY-SA 3.0 |