Timeline for Why is the L2 regularization equivalent to Gaussian prior?
Current License: CC BY-SA 3.0
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| May 6, 2021 at 20:16 | comment | added | 24n8 | Sorry, I think I'm missing the connection between how mean mean minimizes $\ell_2$ norm and that the $\mu$ can be estimated using sample mean means that "normal distribution is equivalent to L2 norm optimization." Can you expand on that (I have the same lack of understanding with L1, but I'm disregarding that for now) | |
| Sep 2, 2016 at 1:24 | comment | added | SQLServerSteve | Perhaps this is not the most mathematically rigorous answer given here, but it's definitely the easiest, most intuitive one for a beginner in L1/L2 regularization to grasp. | |
| Jul 28, 2015 at 9:07 | history | edited | Tim | CC BY-SA 3.0 |
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| Jul 28, 2015 at 8:52 | history | edited | Tim | CC BY-SA 3.0 |
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| Jul 28, 2015 at 8:45 | history | edited | Tim | CC BY-SA 3.0 |
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| Jul 27, 2015 at 17:18 | history | answered | Tim | CC BY-SA 3.0 |