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Aksakal
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One way to answer your question is to answer a similar question: what is the probability that any given number in A was not picked after $N$ iterations?

The answer to this question is: $P=(1-\frac{30}{1000})^N$

Then the answer to your original question is $\frac{\ln (1-p)}{\ln(1-\frac{30}{1000})}$, where $p=!-P$$p=1-P$ is your certain probability.

Also, a word certain usually refers to probability 100% or 1. I'm assuming that you use this word in its different meaning, i.e. "specific but not explicitly named or stated".

One way to answer your question is to answer a similar question: what is the probability that any given number in A was not picked after $N$ iterations?

The answer to this question is: $P=(1-\frac{30}{1000})^N$

Then the answer to your original question is $\frac{\ln (1-p)}{\ln(1-\frac{30}{1000})}$, where $p=!-P$ is your certain probability.

Also, a word certain usually refers to probability 100% or 1. I'm assuming that you use this word in its different meaning, i.e. "specific but not explicitly named or stated".

One way to answer your question is to answer a similar question: what is the probability that any given number in A was not picked after $N$ iterations?

The answer to this question is: $P=(1-\frac{30}{1000})^N$

Then the answer to your original question is $\frac{\ln (1-p)}{\ln(1-\frac{30}{1000})}$, where $p=1-P$ is your certain probability.

Also, a word certain usually refers to probability 100% or 1. I'm assuming that you use this word in its different meaning, i.e. "specific but not explicitly named or stated".

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Aksakal
  • 62.3k
  • 6
  • 106
  • 206

One way to answer your question is to answer a similar question: what is the probability that any given number in A was not picked after $N$ iterations?

The answer to this question is: $P=(1-\frac{30}{1000})^N$

Then the answer to your original question is $\frac{\ln (1-p)}{\ln(1-\frac{30}{1000})}$, where $p$$p=!-P$ is your certain probability.

Also, a word certain usually refers to probability 100% or 1. I'm assuming that you use this word in its different meaning, i.e. "specific but not explicitly named or stated".

One way to answer your question is to answer a similar question: what is the probability that any given number in A was not picked after $N$ iterations?

The answer to this question is: $P=(1-\frac{30}{1000})^N$

Then the answer to your original question is $\frac{\ln (1-p)}{\ln(1-\frac{30}{1000})}$, where $p$ is your certain probability.

One way to answer your question is to answer a similar question: what is the probability that any given number in A was not picked after $N$ iterations?

The answer to this question is: $P=(1-\frac{30}{1000})^N$

Then the answer to your original question is $\frac{\ln (1-p)}{\ln(1-\frac{30}{1000})}$, where $p=!-P$ is your certain probability.

Also, a word certain usually refers to probability 100% or 1. I'm assuming that you use this word in its different meaning, i.e. "specific but not explicitly named or stated".

added 196 characters in body
Source Link
Aksakal
  • 62.3k
  • 6
  • 106
  • 206

One way to answer your question is to answer a similar question: what is the probability that any given number in A was not picked after $N$ iterations?

The answer to this question is: $P=(1-\frac{30}{1000})^N$

Then the answer to your original question is $\frac{\ln (1-p)}{\ln(1-\frac{30}{1000})}$, where $p$ is your certain probability.

One way to answer your question is to answer a similar question: what is the probability that any given number in A was not picked after $N$ iterations?

One way to answer your question is to answer a similar question: what is the probability that any given number in A was not picked after $N$ iterations?

The answer to this question is: $P=(1-\frac{30}{1000})^N$

Then the answer to your original question is $\frac{\ln (1-p)}{\ln(1-\frac{30}{1000})}$, where $p$ is your certain probability.

Source Link
Aksakal
  • 62.3k
  • 6
  • 106
  • 206
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