Skip to main content
13 events
when toggle format what by license comment
Jan 30, 2023 at 23:15 comment added Alexis I am unclear on the difference between your model 3 and $E[Y | X] = \beta_0 + \left(\sqrt{\beta_1}\right)^2 X$. Is your model 3 supposed to be constrained by a previous estimate of your model 1? Or did you mean to provide an example like $E[Y | X] = \beta_0 + \left(\beta_1\right)^{2X}$ or…?
Apr 13, 2017 at 12:44 history edited CommunityBot
replaced http://stats.stackexchange.com/ with https://stats.stackexchange.com/
Dec 31, 2015 at 18:38 answer added meh timeline score: 1
Dec 30, 2015 at 19:11 answer added Harvey Motulsky timeline score: 2
Dec 27, 2015 at 6:47 history tweeted twitter.com/StackStats/status/681003486054608896
Dec 27, 2015 at 5:00 answer added Ott Toomet timeline score: 5
Dec 27, 2015 at 2:15 history edited Ashley Naimi CC BY-SA 3.0
edited body
Dec 27, 2015 at 2:11 comment added Ashley Naimi @Tim, thanks for the comment. I was aware of this transformation as a possibility, but was trying to ask a somewhat different question. I have substantially edited the question, hopefully for the better.
Dec 27, 2015 at 2:10 history edited Ashley Naimi CC BY-SA 3.0
added 1141 characters in body
Dec 26, 2015 at 21:11 history edited gung - Reinstate Monica CC BY-SA 3.0
clarified question in title; removed tag; formatted link; edited
Dec 26, 2015 at 21:02 comment added Tim If you want to estimate $E[Y|X] = \beta_0 + \beta_1^2 X$, simply estimate $E[Y|X] = \beta_0 + \gamma X$ (simple linear regression) and then take $\beta_1 = \sqrt{\gamma}$...
Dec 26, 2015 at 20:54 review First posts
Dec 26, 2015 at 21:11
Dec 26, 2015 at 20:49 history asked Ashley Naimi CC BY-SA 3.0