Timeline for minimum cdf given mean and variance
Current License: CC BY-SA 3.0
19 events
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Jan 11, 2016 at 0:59 | history | edited | Glen_b |
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Jan 3, 2016 at 22:06 | answer | added | Glen_b | timeline score: 2 | |
Jan 3, 2016 at 14:09 | comment | added | whuber♦ | @Glen_b I was hoping that the triviality of the question was due to some typographical error or misunderstanding, but since it hasn't substantially changed through several edits, I have to agree with you: we might as well answer it as it stands. | |
Jan 3, 2016 at 14:07 | history | reopened | whuber♦ | ||
Jan 3, 2016 at 0:24 | comment | added | Glen_b | I think the question is perfectly clear and answerable as it stands. I don't see the difficulty here; the proposed result is obviously false -- an answer would consist simply of any of the (completely obvious) counterexamples. (Yes, it may be that the actual question is different from what was asked - so let's just answer this one and let the OP ask a new one if that turns out to be the case). I have an answer ready to go. | |
Jan 3, 2016 at 0:05 | review | Reopen votes | |||
Jan 3, 2016 at 0:31 | |||||
Jan 2, 2016 at 23:45 | history | edited | omdsoimoin | CC BY-SA 3.0 |
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Jan 2, 2016 at 23:38 | comment | added | gung - Reinstate Monica | Like @whuber I have no earthly idea what your edit might mean. We usually denote the CDF $F(x)$ (& for the normal distribution, $\Phi(x)$). By definition, the CDF outputs a value in $[0,1]$, whether the distribution is normal or not. The PDF is denoted $f(x)$ (/ $\phi(x)$ for a normal). It is most typically thought of as the derivative of the CDF. | |
Jan 2, 2016 at 23:35 | comment | added | omdsoimoin | @whuber, can you explain why the argument in my question ins't right? | |
Jan 2, 2016 at 23:20 | comment | added | whuber♦ | en.wikipedia.org/wiki/… | |
Jan 2, 2016 at 23:18 | comment | added | omdsoimoin | @whuber, can you elaborate? If what that I try to prove isn't correct, can you explain why? | |
Jan 2, 2016 at 22:34 | comment | added | whuber♦ | Asking for such a lower bound makes so little sense that I wonder whether you might be confusing it with the differential entropy. | |
Jan 2, 2016 at 22:33 | history | closed |
Tim whuber♦ |
Needs details or clarity | |
Jan 2, 2016 at 22:06 | comment | added | omdsoimoin | I edited the question with more formal details. | |
Jan 2, 2016 at 22:05 | history | edited | omdsoimoin | CC BY-SA 3.0 |
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Jan 2, 2016 at 21:55 | review | Close votes | |||
Jan 2, 2016 at 22:37 | |||||
Jan 2, 2016 at 21:50 | comment | added | gung - Reinstate Monica | I don't quite follow this. What do you mean by "min $cdf$"? The minimum for a population that is truly distributed as a normal is $-\infty$, so that would be lower than any finite minimum by definition, but I don't know if that is what you are asking about. | |
Jan 2, 2016 at 21:33 | review | First posts | |||
Jan 2, 2016 at 21:50 | |||||
Jan 2, 2016 at 21:32 | history | asked | omdsoimoin | CC BY-SA 3.0 |