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Oct 16, 2016 at 15:30 vote accept mavavilj
Feb 24, 2016 at 13:46 history edited mavavilj CC BY-SA 3.0
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Feb 24, 2016 at 11:34 answer added mavavilj timeline score: 3
Feb 24, 2016 at 10:17 comment added Harald Thomson In case the fisher information $J(\theta)$ is a matrix the size $n \times n$ with $n > 1$ the variance of the parameters are still given by the inverse of the fisher information. i.e. $J(\theta)^{-1}$. However, inverting a matrix is slightly more tricky than inverting a scalar. You need to find the matrix $B$ whose matrix-product with $J(\theta)$ results in the identity matrix $I$.
Feb 24, 2016 at 8:42 history asked mavavilj CC BY-SA 3.0