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Jan 2, 2012 at 18:09 comment added Has QUIT--Anony-Mousse They clearly look Gaussian enough to me. K-means models data with Voronoi cells. It does not seem sensible to me to assume that the best split point is exactly in the middle of the two neighboring means.
Jan 2, 2012 at 13:53 vote accept Nikolaus
Jan 2, 2012 at 12:37 comment added Elvis +1 to this and to Greg Snow. I totally agree with this advice. @Nikolaus I think this looks "gaussian enough" to fit a mixture of gaussians distributions. You don’t want a perfect fit, just a way to check how many clusters there are. In this optic, constraining all components to share the same standard deviation can be a good idea (for the reasons explained by Anony-Mousse).
Jan 2, 2012 at 11:57 comment added Nikolaus Thanks, I didn't know of Levenberg-Marquardt! These clusters are not Gaussian; do you still think Gaussian functions would be the best PDF to fit them to?
Jan 2, 2012 at 10:54 history edited Has QUIT--Anony-Mousse CC BY-SA 3.0
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Jan 2, 2012 at 10:01 history answered Has QUIT--Anony-Mousse CC BY-SA 3.0