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S Jan 27, 2013 at 9:51 history suggested CommunityBot CC BY-SA 3.0
The formula gives the distance squared rather than the distance, a distinction often omitted in literature that is confusing to people learning the topic.
Jan 27, 2013 at 3:11 answer added Joe Sullivan timeline score: 13
Jan 27, 2013 at 3:03 review Suggested edits
S Jan 27, 2013 at 9:51
May 15, 2012 at 18:45 comment added shabbychef Can this result be used to find outlier observations in a Hotelling analysis? By that I mean compute the beta CDF of the rescaled $d_i^2$, and look for values near 1. Could one characterize the rescaled $d_i^2$ as 'leverages' in some way? fascinating.
Jan 4, 2012 at 16:19 history edited user88 CC BY-SA 3.0
edited title
Jan 4, 2012 at 14:17 comment added user8331 The distribution of $d_i^2(\bar X,S)$ is a beta, $n/(n-1)^2 d_i^2(\bar X,S) \sim B(p/2, (n-p-1)/2)$, but I'm still seeking for the distribution of $d^2_i(\mu, S)$. The distributions of the $d^2_i$'s are not independent.
Jan 4, 2012 at 2:26 history tweeted twitter.com/#!/StackStats/status/154388212079534081
Jan 3, 2012 at 17:53 vote accept StasK
Jan 3, 2012 at 17:48 comment added StasK @whuber, roughly along the lines of what jbowman said -- to indicate that this is an observation-level statistic (as opposed to a sample level statistic, like sample mean).
Jan 3, 2012 at 17:35 answer added vinux timeline score: 23
Jan 3, 2012 at 16:57 comment added jbowman @whuber - perhaps to emphasize that it's calculated using an observation from the sample, not a new observation?
Jan 3, 2012 at 16:48 comment added whuber Yes, but what I find confusing is that all the $d_i^2$ must have the same distribution because of the iid assumption, so why maintain a separate subscript?
Jan 3, 2012 at 16:33 comment added StasK @whuber, $d_i^2$ is a function of a random vector $X_i$, and hence is a random variable. Is that what you are asking?
Jan 3, 2012 at 16:32 comment added StasK @cardinal, you are certainly right, I had a thought that it has to be bounded, but it slipped my mind when I was writing this up. A scaled multivariate beta?
Jan 3, 2012 at 16:00 comment added cardinal Just a little off-the-cuff side note, but notice that $X_i - \bar{X}$ is ancillary with respect to $\mu$ and $\sum_i d_i^2(\bar{X},S)$ is equal to a fixed constant (should be $n-p$, or similar, I think) almost surely.
Jan 3, 2012 at 15:35 comment added whuber In the definition of $d_i^2$, do you still view $X_i$ as a random variable or are you now treating it as a fixed vector? Including the subscript suggests the latter, but that seems a little strange.
Jan 3, 2012 at 15:33 history edited whuber CC BY-SA 3.0
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Jan 3, 2012 at 15:13 history asked StasK CC BY-SA 3.0