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May 6, 2016 at 13:59 vote accept Stephen
May 5, 2016 at 18:33 comment added whuber Obviously $x\to\exp(-\lambda x)$ cannot be a CDF (even when limited to positive $x$), because either it decreases (for $\lambda \gt 0$), blows up (for $\lambda \lt 0$), or is forever constant, none of which are possible for any CDF (except an atom at $0$, which is unhelpful). Moreover, when you checked your work you should have found that $\frac{d}{dx}\exp(-\lambda x) = -\lambda\exp(-\lambda x)$ has the wrong sign.
May 5, 2016 at 16:44 history edited dsaxton CC BY-SA 3.0
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May 5, 2016 at 16:41 history edited Greenparker CC BY-SA 3.0
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May 5, 2016 at 14:56 answer added Greenparker timeline score: 7
May 5, 2016 at 14:12 review First posts
May 5, 2016 at 14:32
May 5, 2016 at 14:08 history asked Stephen CC BY-SA 3.0