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May 16, 2016 at 9:40 comment added Glen_b What's the issue here -- do you know what "truncation" means?
May 16, 2016 at 8:26 answer added Achim Zeileis timeline score: 2
May 16, 2016 at 8:05 comment added mef If the distribution is continuous there is no mass point at $m$. It doesn't matter whether inequality is strict or not since $m$ has zero measure.
May 16, 2016 at 2:58 review First posts
May 16, 2016 at 3:15
May 16, 2016 at 2:58 history asked Christine Braun CC BY-SA 3.0