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fixed summation in numerator
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Ryan
Ryan
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For an ARDL(n,m) model using your notation the multiplier is given by:

$\frac{\sum_{i=0}^nb_i}{1-\sum_{j=1}^na_j}$$\frac{\sum_{i=0}^mb_i}{1-\sum_{j=1}^na_j}$

For an ARDL(n,m) model using your notation the multiplier is given by:

$\frac{\sum_{i=0}^nb_i}{1-\sum_{j=1}^na_j}$

For an ARDL(n,m) model using your notation the multiplier is given by:

$\frac{\sum_{i=0}^mb_i}{1-\sum_{j=1}^na_j}$

Source Link
Ryan
Ryan
  • 229
  • 1
  • 6

For an ARDL(n,m) model using your notation the multiplier is given by:

$\frac{\sum_{i=0}^nb_i}{1-\sum_{j=1}^na_j}$