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When two events A$A$ and B$B$ have no result in common

I and my friends just had a little discussion whether the events are independent or dependent if they have no resultoutcome in common. I thought that they have to be independent. When two events are independent, then $P(A)=P(A\mid B)$. Is the information given in the question enough to establish this?

If you look at it as a Venn diagram, then if there is no overlap between A and B, then they are independent. But my friend objected and said that this depends on the sample space.

So let's say we have two events: $P(A)=6/12$, $P(A\mid B)=2/4$, and $P(B)=4/12$, then obviously $P(A\mid B)$ equals $P(A)$. But for me, something smells fishy here.

I know this is more a stochastic question that a statistic question, but maybe someone can help.

I and my friends just had a little discussion whether the events are independent or dependent if they have no result in common. I thought that they have to be independent. When two events are independent, then $P(A)=P(A\mid B)$. Is the information given in the question enough to establish this?

If you look at it as a Venn diagram, then if there is no overlap between A and B, then they are independent. But my friend objected and said that this depends on the sample space.

So let's say we have two events: $P(A)=6/12$, $P(A\mid B)=2/4$, and $P(B)=4/12$, then obviously $P(A\mid B)$ equals $P(A)$. But for me, something smells fishy here.

I know this is more a stochastic question that a statistic question, but maybe someone can help.

I and my friends just had a little discussion whether the events are independent or dependent if they have no outcome in common. I thought that they have to be independent. When two events are independent, then $P(A)=P(A\mid B)$. Is the information given in the question enough to establish this?

If you look at it as a Venn diagram, then if there is no overlap between A and B, then they are independent. But my friend objected and said that this depends on the sample space.

So let's say we have two events: $P(A)=6/12$, $P(A\mid B)=2/4$, and $P(B)=4/12$, then obviously $P(A\mid B)$ equals $P(A)$. But for me, something smells fishy here.

I know this is more a stochastic question that a statistic question, but maybe someone can help.

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chl
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I and my friends just had a little discussion whether the events are independent or dependent if they have no result in common... I thought that they have to be independent. When two events are independent, then P(A)=P(A|B)$P(A)=P(A\mid B)$. Is the information given in the question enough to establish this? If

If you look at it as a vennVenn diagram, then if there is no overlap between A and B, then they are independent. But my friend objected and said that this depends on the sample space. So lets

So let's say we have two events: P(A)=6/12 P(A|B)=2/4$P(A)=6/12$, $P(A\mid B)=2/4$, and P(B=4/12)$P(B)=4/12$, then obviously P(A|B) = as P(A)$P(A\mid B)$ equals $P(A)$. But for me, something smells fishy here. I

I know this is more a stochastic question that a statistic question, but maybe someone can help.

Greetings, A

I and my friends just had a little discussion whether the events are independent or dependent if they have no result in common... I thought that they have to be independent. When two events are independent, then P(A)=P(A|B). Is the information given in the question enough to establish this? If you look at it as a venn diagram, then if there is no overlap between A and B, then they are independent. But my friend objected and said that this depends on the sample space. So lets say we have two events: P(A)=6/12 P(A|B)=2/4 and P(B=4/12), then obviously P(A|B) = as P(A). But for me, something smells fishy here. I know this is more a stochastic question that a statistic question, but maybe someone can help.

Greetings, A

I and my friends just had a little discussion whether the events are independent or dependent if they have no result in common. I thought that they have to be independent. When two events are independent, then $P(A)=P(A\mid B)$. Is the information given in the question enough to establish this?

If you look at it as a Venn diagram, then if there is no overlap between A and B, then they are independent. But my friend objected and said that this depends on the sample space.

So let's say we have two events: $P(A)=6/12$, $P(A\mid B)=2/4$, and $P(B)=4/12$, then obviously $P(A\mid B)$ equals $P(A)$. But for me, something smells fishy here.

I know this is more a stochastic question that a statistic question, but maybe someone can help.

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Adam
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