Timeline for Chi-square test vs. McNemar's test - which test is right for this highly usual situation?
Current License: CC BY-SA 4.0
10 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Sep 8, 2022 at 18:09 | history | edited | kjetil b halvorsen♦ | CC BY-SA 4.0 |
deleted 11 characters in body
|
| Jan 9, 2017 at 13:57 | comment | added | mdewey | You can also test for independence but it answers a different question. Try the later answers in that thread. | |
| Jan 9, 2017 at 13:31 | comment | added | NamelessAmos | @mdewey I was under the impression that samples are to be considered paired only when we have repeated measurements on the same variable (e.g. pre-post) or when we have matched pairs of participants in different treatments? Perhaps I'm confused about the terminology. In any case, yes, every participant answers both questions. If my samples qualify as paired, it would indicate that McNemar's test is the appropriate test. However, two commentators in the Q&A you linked suggest that, in a situation analogous to mine, chi-sq test for independence would be appropriate. So I'm still a bit confused! | |
| Jan 9, 2017 at 13:12 | comment | added | mdewey | Why do you say your samples are not paired? In your question you say that the everybody answered both questions | |
| Jan 9, 2017 at 13:10 | comment | added | NamelessAmos | @mdewey Thank you for the link. I did read it prior to making my post, but unfortunately it did not completely alleviate my confusion... Two separate commentators in the linked post advise the use of the chi-square test of independence. However, the statistics textbooks I've consulted emphasize that the chi-2 test for independence requires two independent samples to work properly. However, as my samples are neither independent nor paired, I'm still a bit confused as to which test applies to my situation. Or am I misunderstanding something? | |
| Jan 9, 2017 at 2:32 | history | tweeted | twitter.com/StackStats/status/818284267117617154 | ||
| Jan 8, 2017 at 15:04 | comment | added | mdewey | Have you already looked at this Q&A stats.stackexchange.com/questions/76875/… which has a very detailed answer. | |
| Jan 8, 2017 at 10:24 | comment | added | ttnphns | McNemar is a test of difference between two paired/repeated-measures samples, i.e. between two variables. Homogeneity chi-square test is a test of of difference between two independent samples; which means that it an association measure between two variables - one taken as "grouping" and the other as "response". For 2x2 situation, standardized version of Chi-sq, the phi coefficient, is equivalent of Pearson correlation coefficient. Will that info help you to decide? | |
| Jan 8, 2017 at 9:52 | review | First posts | |||
| Jan 8, 2017 at 10:06 | |||||
| Jan 8, 2017 at 9:51 | history | asked | NamelessAmos | CC BY-SA 3.0 |