Timeline for Significance test for two mean differences? Like a t-test but for comparing differences
Current License: CC BY-SA 3.0
8 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Apr 3, 2012 at 0:26 | comment | added | Captain Murphy | @ Shabbychef -- that is essentially what I would like to do. But I need a sample size to calculate a t-test, don't I? How can I do a t-test on a mean when it is a summary score and not a distribution? Typically when I calculate a t ratio, I need a distribution so that I can find a standard error and mean. I'm not sure how to do that here. | |
| Mar 31, 2012 at 12:46 | comment | added | rolando2 | Actually I'm thinking that pairing would only matter if the x-differences were paired with the y-differences. | |
| Mar 31, 2012 at 1:57 | comment | added | Aaron - mostly inactive |
Are x1 and x2 paired (and y1 and y2 also)? You don't mention it but from the pattern of your sample data it seems likely. You would use a different test if they are paired than if they aren't.
|
|
| Mar 30, 2012 at 23:47 | comment | added | shabbychef |
I'm confused, because the difference in sample means is the sample mean of the differences. so why not do a $t$-test on whether the mean of x1 - x2 is different from that of y1 - y2?
|
|
| Mar 30, 2012 at 23:41 | answer | added | John | timeline score: 1 | |
| Mar 30, 2012 at 23:34 | answer | added | rolando2 | timeline score: 4 | |
| Mar 30, 2012 at 23:02 | comment | added | Roman Luštrik | A t-test is not appropriate here (see wiki about assumptions). Chi-square test comes to mind here, where you would compare if the observer number of 0/1 is expected or not. | |
| Mar 30, 2012 at 22:11 | history | asked | Captain Murphy | CC BY-SA 3.0 |