Timeline for What justifies this calculation of the derivative of a matrix function?
Current License: CC BY-SA 3.0
11 events
when toggle format | what | by | license | comment | |
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Jul 6, 2022 at 16:41 | answer | added | zzzhhh | timeline score: 0 | |
Jan 24, 2017 at 4:36 | vote | accept | MoneyBall | ||
Jan 23, 2017 at 0:47 | history | tweeted | twitter.com/StackStats/status/823331399474221056 | ||
Jan 22, 2017 at 23:37 | comment | added | Brian Borchers | Between the second and third line he's let $f(A)=AB$. Between the second and third line he's used the product rule. later he uses the chain rule to get rid of $f()$. | |
Jan 22, 2017 at 21:34 | history | edited | whuber♦ | CC BY-SA 3.0 |
edited tags; edited title
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Jan 22, 2017 at 21:13 | answer | added | whuber♦ | timeline score: 22 | |
Jan 22, 2017 at 17:18 | history | edited | MoneyBall | CC BY-SA 3.0 |
created next line
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Jan 22, 2017 at 17:18 | comment | added | MoneyBall | @whuber I see. Given the assumptions, I still don't understand how the transition happened from second to third line where he introduces $\circ$. | |
Jan 22, 2017 at 17:07 | comment | added | whuber♦ | He must be making special assumptions about the dimensions of $A$, $B$, and $C$, for otherwise this formula makes no sense in general. On the left hand side $A$ must be an $i\times j$ matrix, $B$ a $j\times j$ matrix, and $C$ an $i\times m$ matrix for arbitrary non-negative integers $i,j,m$. But then the products on the right would not be defined unless $i=m$. | |
Jan 22, 2017 at 16:49 | history | edited | MoneyBall | CC BY-SA 3.0 |
deleted 156 characters in body
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Jan 22, 2017 at 16:43 | history | asked | MoneyBall | CC BY-SA 3.0 |