Timeline for Combine crude events and Hazard Ratio in Meta-analysis
Current License: CC BY-SA 3.0
5 events
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| Apr 20, 2017 at 20:17 | comment | added | Björn | c) If you have different types of data, then you would normally not be able to use simple graphical user interface type meta-analysis programs (such as RevMan etc.) and would normally have to use some statistics package that lets you specify a different (log-)likelihood for each trial. Almost any serious statistics package can do that. Options include e.g. PROC NLMIXED or PROC MCMC in SAS, or Stan (easily accessed e.g. via the rstan R package), or stats4:::mle() in R, or many others. | |
| Apr 20, 2017 at 20:11 | comment | added | Björn | b) If you have the hazard ratio + CI (or standard error), then you can back-calculate the number of events in a 1:1 randomized trial the standard error of the log-hazard ratio is approximately $2/\sqrt{y_i}$, where $y_i$ is the total number of events in both treatment groups combined and the confidence interval is approximately $\log \text{HR} \pm 1.96 \text{SE}$. | |
| Apr 20, 2017 at 20:06 | comment | added | Björn | a) Looking only at the number of patients with an event is problematic, if the distribution of drop-out times differs between groups. | |
| Apr 20, 2017 at 19:12 | comment | added | user89547235 | Thank you for your exhaustive reply. Some things I can't understand. Fact is, I have HRs, C.I., possibly a median time of FU and the number of the two whole treatment groups. The only thing I need and I don't have is the number of event; which, based on what you said, I would not be able to calculate in this setting. am I right? On the other hand, I have several studies with number of events and number of total group patients... but not Hazard Ratios. You can put that into your meta-analyzer, but how do you put event number for one study and Hazard Ratio for another study in your analysis? | |
| Apr 20, 2017 at 17:44 | history | answered | Björn | CC BY-SA 3.0 |