Timeline for Ternary diagrams in scatter plot matrix (pairs) with R "compositions"
Current License: CC BY-SA 3.0
18 events
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| Apr 22, 2017 at 2:37 | answer | added | Antoni Parellada | timeline score: 2 | |
| Apr 22, 2017 at 2:30 | history | edited | Antoni Parellada | CC BY-SA 3.0 |
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| Apr 22, 2017 at 1:43 | history | edited | Antoni Parellada | CC BY-SA 3.0 |
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| Apr 22, 2017 at 1:12 | history | edited | Antoni Parellada | CC BY-SA 3.0 |
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| Apr 22, 2017 at 0:15 | history | edited | Antoni Parellada | CC BY-SA 3.0 |
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| Apr 21, 2017 at 23:18 | history | edited | Antoni Parellada | CC BY-SA 3.0 |
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| Apr 21, 2017 at 23:08 | history | edited | Antoni Parellada | CC BY-SA 3.0 |
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| Apr 21, 2017 at 23:02 | history | edited | Antoni Parellada | CC BY-SA 3.0 |
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| Apr 21, 2017 at 22:43 | history | edited | Antoni Parellada | CC BY-SA 3.0 |
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| Apr 21, 2017 at 22:30 | history | edited | Antoni Parellada | CC BY-SA 3.0 |
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| Apr 21, 2017 at 21:44 | history | edited | Antoni Parellada | CC BY-SA 3.0 |
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| Apr 21, 2017 at 21:20 | history | edited | Antoni Parellada | CC BY-SA 3.0 |
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| Apr 21, 2017 at 20:43 | history | edited | Antoni Parellada | CC BY-SA 3.0 |
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| Apr 21, 2017 at 20:30 | history | edited | Antoni Parellada | CC BY-SA 3.0 |
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| Apr 21, 2017 at 19:26 | comment | added | Antoni Parellada |
@whuber Thank you! I'll reopen the question on SO with the code of what I tried - it may not survive since it got a bunch of calls for closure; and if I start a new question, I may be called on it, but I digress. Depending on how it goes, I'll leave the question open (if you are not against it), or come back to delete it. Yes, ellipses is the function in the package. Finally, I do think you answered my more meaningful question (1) to the point that if you happened not to be exactly correct, it wouldn't make any conceptual difference.
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| Apr 21, 2017 at 19:10 | comment | added | whuber♦ |
(2) sounds like it's purely an R question: after all, if you have the code to draw one curve (they're evidently not ellipses!), iteration will draw as many curves as you like. If you want this to fly on Stack Overflow, supply a simple dataset so that people can reproduce your computation. For (1) I don't know the answer, because I don't want to research your references, but the first thing that comes to mind is to plot each pair of components $(X_i,X_j)$ against the sum of all other components: that gives a meaningful three-component mixture.
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| Apr 21, 2017 at 17:26 | history | edited | Antoni Parellada | CC BY-SA 3.0 |
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| Apr 21, 2017 at 17:17 | history | asked | Antoni Parellada | CC BY-SA 3.0 |