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Mark L. Stone
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There's been a lot of beating around the bush in this thread regarding whether the Hessian has to be positive (semi)definite at a local minimum. So I will make a clear statement on that.

Presuming the objective function and all constraint functions are twice continuously differentiable, then at any local minimum, the Hessian of the Lagrangian projected into the null space of the Jacobian of active constraints must be positive semidefinite. I.e., if $Z$ is a basis for the null space of the Jacobian of active constraints, then $Z^T*(\text{Hessian of Lagrangian})*Z$ must be positive semidefinite. This must be positive definite for a strict local minimum.

So the Hessian of the objective function in a constrained problem having active constraint(s) need not be positive semidefinite if there are active constraints.

Notes:

  1. Active constraints consist of all equality constraints, plus inequality constraints which are satisfied with equality.

  2. See the definition of the Lagrangian at https://www.encyclopediaofmath.org/index.php/Karush-Kuhn-Tucker_conditions .

  3. If all constraints are linear, then the Hessian of the Lagrangian = Hessian of the objective function because the 2nd derivatives of linear functions are zero. But you still need to do the projection jazz if any of these constraints are active. Note that lower or upper bound constraints are particular cases of linear inequality constraints. If the only constraints which are active are bound constraints, the projection of the Hessian into the null space of the Jacobian of active constraints amounts to eliminating the rows and columns of the Hessian corresponding to those components on their bounds.

  4. Because Lagrange multipliers of inactive constraints are zero, if there are no active constraints, the Hessian of the Lagrangian = the Hessian of the objective function, and the Identity matrix is a basis for the null space of the Jacobian of active constraints, which results in the simplification of the criterion being the familiar condition that the Hessian of the objective function be positive senidefinitesemidefinite at a local minimum (positive definite if a strict local minimum).

There's been a lot of beating around the bush in this thread regarding whether the Hessian has to be positive (semi)definite at a local minimum. So I will make a clear statement on that.

Presuming the objective function and all constraint functions are twice continuously differentiable, then at any local minimum, the Hessian of the Lagrangian projected into the null space of the Jacobian of active constraints must be positive semidefinite. I.e., if $Z$ is a basis for the null space of the Jacobian of active constraints, then $Z^T*(\text{Hessian of Lagrangian})*Z$ must be positive semidefinite. This must be positive definite for a strict local minimum.

So the Hessian of the objective function in a constrained problem having active constraint(s) need not be positive semidefinite if there are active constraints.

Notes:

  1. Active constraints consist of all equality constraints, plus inequality constraints which are satisfied with equality.

  2. See the definition of the Lagrangian at https://www.encyclopediaofmath.org/index.php/Karush-Kuhn-Tucker_conditions .

  3. If all constraints are linear, then the Hessian of the Lagrangian = Hessian of the objective function because the 2nd derivatives of linear functions are zero. But you still need to do the projection jazz if any of these constraints are active. Note that lower or upper bound constraints are particular cases of linear inequality constraints. If the only constraints which are active are bound constraints, the projection of the Hessian into the null space of the Jacobian of active constraints amounts to eliminating the rows and columns of the Hessian corresponding to those components on their bounds.

  4. Because Lagrange multipliers of inactive constraints are zero, if there are no active constraints, the Hessian of the Lagrangian = the Hessian of the objective function, and the Identity matrix is a basis for the null space of the Jacobian of active constraints, which results in the simplification of the criterion being the familiar condition that the Hessian of the objective function be positive senidefinite at a local minimum (positive definite if a strict local minimum).

There's been a lot of beating around the bush in this thread regarding whether the Hessian has to be positive (semi)definite at a local minimum. So I will make a clear statement on that.

Presuming the objective function and all constraint functions are twice continuously differentiable, then at any local minimum, the Hessian of the Lagrangian projected into the null space of the Jacobian of active constraints must be positive semidefinite. I.e., if $Z$ is a basis for the null space of the Jacobian of active constraints, then $Z^T*(\text{Hessian of Lagrangian})*Z$ must be positive semidefinite. This must be positive definite for a strict local minimum.

So the Hessian of the objective function in a constrained problem having active constraint(s) need not be positive semidefinite if there are active constraints.

Notes:

  1. Active constraints consist of all equality constraints, plus inequality constraints which are satisfied with equality.

  2. See the definition of the Lagrangian at https://www.encyclopediaofmath.org/index.php/Karush-Kuhn-Tucker_conditions .

  3. If all constraints are linear, then the Hessian of the Lagrangian = Hessian of the objective function because the 2nd derivatives of linear functions are zero. But you still need to do the projection jazz if any of these constraints are active. Note that lower or upper bound constraints are particular cases of linear inequality constraints. If the only constraints which are active are bound constraints, the projection of the Hessian into the null space of the Jacobian of active constraints amounts to eliminating the rows and columns of the Hessian corresponding to those components on their bounds.

  4. Because Lagrange multipliers of inactive constraints are zero, if there are no active constraints, the Hessian of the Lagrangian = the Hessian of the objective function, and the Identity matrix is a basis for the null space of the Jacobian of active constraints, which results in the simplification of the criterion being the familiar condition that the Hessian of the objective function be positive semidefinite at a local minimum (positive definite if a strict local minimum).

Source Link
Mark L. Stone
  • 13.5k
  • 1
  • 38
  • 58

There's been a lot of beating around the bush in this thread regarding whether the Hessian has to be positive (semi)definite at a local minimum. So I will make a clear statement on that.

Presuming the objective function and all constraint functions are twice continuously differentiable, then at any local minimum, the Hessian of the Lagrangian projected into the null space of the Jacobian of active constraints must be positive semidefinite. I.e., if $Z$ is a basis for the null space of the Jacobian of active constraints, then $Z^T*(\text{Hessian of Lagrangian})*Z$ must be positive semidefinite. This must be positive definite for a strict local minimum.

So the Hessian of the objective function in a constrained problem having active constraint(s) need not be positive semidefinite if there are active constraints.

Notes:

  1. Active constraints consist of all equality constraints, plus inequality constraints which are satisfied with equality.

  2. See the definition of the Lagrangian at https://www.encyclopediaofmath.org/index.php/Karush-Kuhn-Tucker_conditions .

  3. If all constraints are linear, then the Hessian of the Lagrangian = Hessian of the objective function because the 2nd derivatives of linear functions are zero. But you still need to do the projection jazz if any of these constraints are active. Note that lower or upper bound constraints are particular cases of linear inequality constraints. If the only constraints which are active are bound constraints, the projection of the Hessian into the null space of the Jacobian of active constraints amounts to eliminating the rows and columns of the Hessian corresponding to those components on their bounds.

  4. Because Lagrange multipliers of inactive constraints are zero, if there are no active constraints, the Hessian of the Lagrangian = the Hessian of the objective function, and the Identity matrix is a basis for the null space of the Jacobian of active constraints, which results in the simplification of the criterion being the familiar condition that the Hessian of the objective function be positive senidefinite at a local minimum (positive definite if a strict local minimum).