What I know (not very sure)

my specific question is: is delta(x1bar) in the equation the std.error in the glm result? Do I need to divide by n any more?

What I know (not very sure, and would like to get verified)

so, is delta(x1bar) in the equation the std.error in the glm result? I don't need to divide by n any more, right (since the std.error in the glm result in already the standard deviation of the mean)?

Comparing ID == 'X02' to 'X03':

z = (-2.525e-01 - 2.081e+01) / sqrt(1.721e+00^2 + 7.562e+03^2)
= -0.002785

is this correct? Thanks-

for example the data has a binary response 'y', a numerical predictor week, and some categorical/factor predictors: ap, hilo, ID, trt:

for example the data has a binary response y, a numerical predictor week, and some categorical/factor predictors: ap, hilo, ID, trt: