Timeline for Converting annual to daily mortality rate
Current License: CC BY-SA 3.0
9 events
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| Jul 24, 2017 at 18:15 | comment | added | Aywfto | Ahh! i see. You're right -- it looks like its 1-EXP(LN(1-[annual mortality rate])/365) ^is that the standard one for calculating with compound interest? That makes sense then! | |
| Jul 22, 2017 at 20:02 | comment | added | whuber♦ | Your expression will not work, Christina, because the parentheses are unbalanced. One doesn't need to guess about the reason for the formula: this is a standard one for calculating with compound interest. | |
| Jul 22, 2017 at 18:22 | comment | added | Aywfto | Thanks for this answer! I double checked the parentheses... they seem to be what I wrote above? Maybe the original person who made the workbook didn't do it right? As for rate, I mean mortality rate. @whuber If the result from our formula is similar to the 0.03082/365, do you have a guess as to why the original person (who I can't contact anymore) used a more complicated formula (as opposed to plain old [annual mortality rate]/365)? | |
| Jul 20, 2017 at 22:37 | history | edited | whuber♦ |
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| Jul 20, 2017 at 22:33 | comment | added | whuber♦ | I suspect you haven't quoted the formula correctly; the parentheses are misplaced. The correct one is $$1-(1-0.03082)^{1/365} = 1-\exp\left(\frac{1}{365}\log\left(1-0.03082\right)\right)\\=0.0000857632 \approx 0.0000844384 = \frac{0.03082}{365}.$$ | |
| Jul 8, 2017 at 4:08 | comment | added | meh | You should ask here - math.stackexchange.com . I'm not sure about what exactly you mean by rate, but notice that $(1-AR) \neq (1- \frac{AR}{365})^{365} $ | |
| Jul 8, 2017 at 4:03 | answer | added | Michael R. Chernick | timeline score: 1 | |
| Jul 8, 2017 at 3:34 | review | First posts | |||
| Jul 8, 2017 at 6:05 | |||||
| Jul 8, 2017 at 3:31 | history | asked | Aywfto | CC BY-SA 3.0 |