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Michael R. Chernick
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This is true for any continuous distribution and not just a normal. You simply calculate the sample standard deviation and divide it by the square root of n.

Let m be the the mean for the sample sum the squared deviations of the observations Xi for the sample mean m divide by n-1 (of the unbiased variance estimate) and take the square root for the sample standard deviation estimate. Then divide by the square root of n to get thestandardthe standard error.

This is true for any continuous distribution and not just a normal. You simply calculate the sample standard deviation and divide it by the square root of n.

Let m be the the mean for the sample sum the squared deviations of the observations Xi for the sample mean m divide by n-1 (of the unbiased variance estimate) and take the square root for the sample standard deviation estimate. Then divide by the square root of n to get thestandard error.

This is true for any continuous distribution and not just a normal. You simply calculate the sample standard deviation and divide it by the square root of n.

Let m be the the mean for the sample sum the squared deviations of the observations Xi for the sample mean m divide by n-1 (of the unbiased variance estimate) and take the square root for the sample standard deviation estimate. Then divide by the square root of n to get the standard error.

Source Link
Michael R. Chernick
  • 43.2k
  • 28
  • 85
  • 159

This is true for any continuous distribution and not just a normal. You simply calculate the sample standard deviation and divide it by the square root of n.

Let m be the the mean for the sample sum the squared deviations of the observations Xi for the sample mean m divide by n-1 (of the unbiased variance estimate) and take the square root for the sample standard deviation estimate. Then divide by the square root of n to get thestandard error.