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Sep 17, 2018 at 11:50 comment added Christoph Hanck See also stats.stackexchange.com/questions/207264/…
Nov 20, 2017 at 20:27 vote accept Candamir
Nov 20, 2017 at 20:26 comment added Alecos Papadopoulos @Candamir In the sense that $[\hat \rho(j) - \rho(j)] = O_p(n^{-1/2})$, yes.
Nov 20, 2017 at 19:43 comment added Candamir Thank you! Does this imply a convergence rate of $n^{-1/2}$? Apologies if this is obvious to you.
Nov 20, 2017 at 19:01 history answered Alecos Papadopoulos CC BY-SA 3.0