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Feb 1, 2018 at 22:03 comment added Prasqui @JanKukacka No the weight, but the error go to zero, so the penalty term become the most relevant in the formula. Anyway the answer of hxd1011 was very simple and clear, but since usually no one mentions it, i was a bit confused.
Feb 1, 2018 at 2:01 history tweeted twitter.com/StackStats/status/958882875964837889
S Jan 31, 2018 at 21:41 history suggested smci CC BY-SA 3.0
clarification
Jan 31, 2018 at 21:38 review Suggested edits
S Jan 31, 2018 at 21:41
S Jan 31, 2018 at 19:14 history edited gung - Reinstate Monica CC BY-SA 3.0
corrected spelling
S Jan 31, 2018 at 19:14 history suggested StatsSorceress CC BY-SA 3.0
corrected spelling
Jan 31, 2018 at 18:56 review Suggested edits
S Jan 31, 2018 at 19:14
Jan 31, 2018 at 18:06 comment added Vladislavs Dovgalecs You want to trade some error on the training set for a lower error on validation set. You don't want to overfit on the training set. I suggest to do a bit reading on how training, validation and test errors are related and controlled.
Jan 31, 2018 at 18:06 comment added Jan Kukacka What exactly do you mean by lambda*w? If the weights go to zero, also the L2 penalty term becomes smaller.
Jan 31, 2018 at 18:03 answer added Jan Kukacka timeline score: 6
Jan 31, 2018 at 17:52 vote accept Prasqui
Jan 31, 2018 at 17:31 answer added Haitao Du timeline score: 12
Jan 31, 2018 at 17:27 review First posts
Jan 31, 2018 at 19:03
Jan 31, 2018 at 17:26 history asked Prasqui CC BY-SA 3.0