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Feb 3, 2021 at 2:23 history edited kjetil b halvorsen
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Feb 3, 2018 at 23:11 history tweeted twitter.com/StackStats/status/959927299977240576
Feb 3, 2018 at 20:22 comment added Orlando Please take a look at my new edit, if you are interested. Hopefully I did not commit any mistake.
Feb 3, 2018 at 20:21 history edited Orlando CC BY-SA 3.0
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Feb 3, 2018 at 19:52 comment added Orlando That's a shame, but thank you anyway!
Feb 3, 2018 at 19:50 comment added whuber Not closed form, no. Possibly under very special assumptions about the distributions of $A$ and $X$ that could be done, but not generally: the correlations make it extremely messy.
Feb 3, 2018 at 19:48 comment added Orlando Yes, that's a great point about it not being non-negative. But still, do you believe there is any hope to obtain some form of closed-form expression for the covariance matrix? (in terms of what we \emph{know}: the expectations and covariances between the different components of $\mathbf{A}$ and $\mathbf{X}$). Thanks!
Feb 3, 2018 at 19:46 comment added whuber In some extremely general sense the marginals are linear combinations of interdependent $\chi^2(2)$ distributions, but there's no hope they even remotely resemble a $\chi^2$: they are just as likely to have negative values as positive ones. For a glimmer of what this might look like, and a reference, see stats.stackexchange.com/questions/48378.
Feb 3, 2018 at 19:44 history edited Orlando CC BY-SA 3.0
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Feb 3, 2018 at 19:39 review First posts
Feb 3, 2018 at 20:22
Feb 3, 2018 at 19:37 history asked Orlando CC BY-SA 3.0