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Would love some help.

I am trying to convert results I am finding in scientific articles into relative risks so that I can compare studies in a meta analysis (if there is enough homogeneity in the studies).

I came across this: Interventiona study entitled "Intervention to improve practices of prescribing appropriate medication before an operation; pre-and-post-intervention studystudy".

In the pre intervention-intervention group, 16 out of 233 patients (so 217 with correct prescription) had an incorrect prescription and post intervention 3 out of 137 patients (134 with correct) had an incorrect prescription.

In the paper, a p-value of 0.046 was given, using FishersFisher's exact test. I checked it using a hand calculation and got 0.049. When I put this result into an RR calculator, I get a RR of 0.32 [0.09, 1.07]. Now I am a relative stats rookie but I thought the 95% CI should not cross 1 if my p-value for comparing two proportions is below 0.05. Confused! Many thanks for your time!

Would love some help.

I am trying to convert results I am finding in scientific articles into relative risks so that I can compare studies in a meta analysis (if there is enough homogeneity in the studies).

I came across this: Intervention to improve practices of prescribing appropriate medication before an operation; pre-and-post-intervention study.

In the pre intervention group 16 out of 233 patients (so 217 with correct prescription) had an incorrect prescription and post intervention 3 out of 137 patients (134 with correct) had an incorrect prescription.

In the paper, a p-value of 0.046 was given, using Fishers exact test. I checked it using a hand calculation and got 0.049. When I put this result into an RR calculator, I get a RR of 0.32 [0.09, 1.07]. Now I am a relative stats rookie but I thought the 95% CI should not cross 1 if my p-value for comparing two proportions is below 0.05. Confused! Many thanks for your time!

I am trying to convert results I am finding in scientific articles into relative risks so that I can compare studies in a meta analysis (if there is enough homogeneity in the studies).

I came across a study entitled "Intervention to improve practices of prescribing appropriate medication before an operation; pre-and-post-intervention study".

In the pre-intervention group, 16 out of 233 patients (so 217 with correct prescription) had an incorrect prescription and post intervention 3 out of 137 patients (134 with correct) had an incorrect prescription.

In the paper, a p-value of 0.046 was given, using Fisher's exact test. I checked it using a hand calculation and got 0.049. When I put this result into an RR calculator, I get a RR of 0.32 [0.09, 1.07]. Now I am a relative stats rookie but I thought the 95% CI should not cross 1 if my p-value for comparing two proportions is below 0.05.

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Michael R. Chernick
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Would love some help.

I am trying to convert results I am finding in scientific articles into relative risks so thatIthat I can compare studies in a meta analysis (if there is enough homogeneity in the studies).

I came across this: Intervention to improve practices of prescribing appropriate medication before an operation; pre-and-post-intervention study.

In the pre intervention group 16 out of 233 patients (so 217 with correct prescription) had an incorrect prescription and post intervention 3 out of 137 patients (134 with correct) had an incorrect prescription.

In the paper, a p-value of 0.046 was given, using Fishers exact test. I checked it using a hand calculation and got 0.049. When I put this result into anyan RR calculator, I get a RR of 0.32 [0.09, 1.07]. Now I am a relative stats rookie but I thought the 95 %CI95% CI should not cross 1 if my p-value for comparing two proportions is below 0.05. Confused! Many thanks for your time!

Would love some help.

I am trying to convert results I am finding in scientific articles into relative risks so thatI can compare studies in a meta analysis (if there is enough homogeneity in the studies).

I came across this: Intervention to improve practices of prescribing appropriate medication before an operation; pre-and-post-intervention study.

In the pre intervention group 16 out of 233 patients (so 217 with correct prescription) had an incorrect prescription and post intervention 3 out of 137 patients (134 with correct) had an incorrect prescription.

In the paper a p-value of 0.046 was given, using Fishers exact test. I checked it using a hand calculation and got 0.049. When I put this result into any RR calculator, I get a RR of 0.32 [0.09, 1.07] Now I am a relative stats rookie but thought the 95 %CI should not cross 1 if my p-value for comparing two proportions is below 0.05. Confused! Many thanks for your time!

Would love some help.

I am trying to convert results I am finding in scientific articles into relative risks so that I can compare studies in a meta analysis (if there is enough homogeneity in the studies).

I came across this: Intervention to improve practices of prescribing appropriate medication before an operation; pre-and-post-intervention study.

In the pre intervention group 16 out of 233 patients (so 217 with correct prescription) had an incorrect prescription and post intervention 3 out of 137 patients (134 with correct) had an incorrect prescription.

In the paper, a p-value of 0.046 was given, using Fishers exact test. I checked it using a hand calculation and got 0.049. When I put this result into an RR calculator, I get a RR of 0.32 [0.09, 1.07]. Now I am a relative stats rookie but I thought the 95% CI should not cross 1 if my p-value for comparing two proportions is below 0.05. Confused! Many thanks for your time!

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Pepps
  • 51
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  • 3

Would love some help.

I am trying to convert results I am finding in scientific articles into relative risks so thatI can compare studies in a meta analysis (if there is enough homogeneity in the studies).

I came across this: Intervention to improve practices of prescribing appropriate medication before an operation; pre-and-post-intervention study.

In the pre intervention group 16 out of 233 patients (so 217 with correct prescription) had an incorrect prescription and post intervention 3 out of 137 patients (134 with correct) had an incorrect prescription.

In the papepaper a p-value of 0.046 was given, using Fishers exact test. I checked it using a hand calculation and got 0.049. When I put this result into any RR calculator, I get a RR of 0.32 [0.09, 1.07] Now I am a relative stats rookie but thought the 95 %CI should not cross one1 if my p-value for comparing two proportions is below 0.05. Confused! Many thanks for your time!

Would love some help.

I am trying to convert results I am finding in scientific articles into relative risks so thatI can compare studies in a meta analysis (if there is enough homogeneity in the studies).

I came across this: Intervention to improve practices of prescribing appropriate medication before an operation; pre-and-post-intervention study.

In the pre intervention group 16 out of 233 patients (so 217 with correct prescription) had an incorrect prescription and post intervention 3 out of 137 patients (134 with correct) had an incorrect prescription.

In the pape a p-value of 0.046 was given, using Fishers exact test. I checked it using a hand calculation and got 0.049. When I put this result into any RR calculator, I get a RR of 0.32 [0.09, 1.07] Now I am a relative stats rookie but thought the 95 %CI should not cross one if my p-value for comparing two proportions is below 0.05. Confused! Many thanks for your time!

Would love some help.

I am trying to convert results I am finding in scientific articles into relative risks so thatI can compare studies in a meta analysis (if there is enough homogeneity in the studies).

I came across this: Intervention to improve practices of prescribing appropriate medication before an operation; pre-and-post-intervention study.

In the pre intervention group 16 out of 233 patients (so 217 with correct prescription) had an incorrect prescription and post intervention 3 out of 137 patients (134 with correct) had an incorrect prescription.

In the paper a p-value of 0.046 was given, using Fishers exact test. I checked it using a hand calculation and got 0.049. When I put this result into any RR calculator, I get a RR of 0.32 [0.09, 1.07] Now I am a relative stats rookie but thought the 95 %CI should not cross 1 if my p-value for comparing two proportions is below 0.05. Confused! Many thanks for your time!

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Source Link
Michael R. Chernick
  • 43.2k
  • 28
  • 85
  • 159
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Source Link
Pepps
  • 51
  • 1
  • 3
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