Timeline for Chi-square test for more than 2 x 2 tables
Current License: CC BY-SA 4.0
5 events
when toggle format | what | by | license | comment | |
---|---|---|---|---|---|
Jun 12, 2018 at 14:04 | vote | accept | Tamas | ||
Jun 9, 2018 at 5:38 | history | post merged (destination) | |||
Jun 8, 2018 at 14:19 | comment | added | F. Tusell | You can compute the chi-square statictic $\sum_{i,j}(X_{ij} - E_{ij})^2/E_{ij}$ with $X_{ij}$ the observed and $E_{ij}$ the observed counts in cell $(i,j)$. Under the hypothesis of homogeneity of the three methods, the expected counts can be obtained from the marginal counts. This tests the null hypothesis that the three methods are homogeneous versus the alternative of at least one different. You could test pairs, but then you would have to take into account the multiple testing when fixing the significance level. | |
Jun 8, 2018 at 12:29 | comment | added | Tamas | Thank you. There are no other identifiable factors to consider. How can we test the three distributions over chi-square test compared to each other? Could you give an example? | |
Jun 8, 2018 at 10:44 | history | answered | F. Tusell | CC BY-SA 4.0 |